In OOP:$this->name is property of the object which is defined by the class and is accessible globally within the object.$name is variable used inside the class method and is accessible locally only within the object method (a function) Very briefly: class myClass{ private $name = “record.log”; function myMethod(){ $name=”this exists only in the method myMethod()”; … Read more
why should we use inheritance between A (super) & B (sub) instead of creating them separately and instantiate A from B? [closed] solved why should we use inheritance between A (super) & B (sub) instead of creating them separately and instantiate A from B? [closed]
There is no benefit to packing as much as possible into a line of code. Separate it out as much as possible, make it easy to read. Strictly speaking, there is no need to call join() in this instance. The purpose of join is to make one thread wait for another thread to finish, but … Read more
To take the first line A a1 = new A();, A a1 is the reference to an object of type A, and A() is a call to the constructor that creates a new instance of A. If class B subclasses A, then you can write a1 = new B();, since a1 is a reference to … Read more
That’s the definition of an abstract class. You cannot create an instance of it, only a type derived from it. Think of something like a fruit. You cannot have a fruit sitting on the table. It must be a certain type of fruit, such as an orange or an apple. In this case, fruit would … Read more
The problem is that you define a type (account) in the class. account is a type so you should not declare it in the class : struct account { std::string name; float money; short pin; }; and then, the class becomes : class CBank { public: CBank(); account acc; std::vector<account> add; }; and the main … Read more
Question 1: Honestly, this is the most basic practical object-oriented question out there. If you don’t understand it, you need to go talk to someone. True or False: Local variables may be declared private. Local variables can never be accessed by outside code; it makes no sense to declare them private. True or False: Formal … Read more
In a Java class, I can see that a class object and variable can have same name. Which value will be printed if they have same scope? solved In a Java class, I can see that a class object and variable can have same name. Which value will be printed if they have same scope?
Java passes a reference to an object in a method. You can call it a pointer if you want. Let’s say you have the object myBar in the class foo and you pass it to the change it method. It doesn’t pass the object itself it passes a reference to that object (a pointer if … Read more
From https://docs.python.org/2/tutorial/classes.html : The simplest form of class definition looks like this: class ClassName: <statement-1> . . . <statement-N> 0 solved OOP in python version 3.5? [closed]
simple answer: NO. here is a nice article that points out .. how the definition for a “real” OO language.. can not be done. There are different relationships between object orientation and computer languages: support of OO, ubiquitous use of OO, and enforcement of OO. Again, I’d recommend some effort to be unambiguous: e.g. “Java … Read more
Can any one explain me the actual concept of Creating and Initialising an object in java?why a default constructor is used in initialising an object [closed] solved Can any one explain me the actual concept of Creating and Initialising an object in java?why a default constructor is used in initialising an object [closed]
In Either one of the code above, the query will just be 1 $a = Flight::find(1); is same as select * from `flights` where `flights`.`id` = 1 limit 1` Since $a & $b are 2 different variables, though they are calling the same Eloquent function, the queries are different. So the code above will result … Read more
class super(object): def __init__(self, **kwargs): self.abc = kwargs.pop(‘abc’, None) self.xyz = kwargs.pop(‘xyz’, None) class sub(super): def __init__(self, *args, **kwargs): super().__init__(**kwargs) self.pqr = kwargs.pop(‘pqr’, None) self.sty = kwargs.pop(‘sty’, None) self.contain = args[0] obj_super = super(abc=1, xyz = 2) obj_sub = sub(obj_super, pqr =3, sty=4) print(obj_sub.contain.abc) solved Passing Object of SuperClass to the SubClass Constructor in Python
What does no match for ‘operator>>’ (operand types are ‘std::istream’ {aka ‘std::basic_istream’} and ‘float*’) mean? [closed] solved What does no match for ‘operator>>’ (operand types are ‘std::istream’ {aka ‘std::basic_istream‘} and ‘float*’) mean? [closed]