Use it like this, assuming your name field SELECT name, COUNT(id) as number_of_searches FROM profiledb WHERE name=”dog” 4 solved How to select the number of names equal to value and save the number of searches found into a variable [closed]
OK, so, your database actually only needs one user (possibly also known as a schema, depending on your database), unless you want to limit who can do what. Then, you need to configure your database to allow remote connections. Once that’s done, you’ll be able to get something called a “connection string”, which can be … Read more
Practically any database should be able to run such queries. In the case of SQL, using a simple WHERE … LIKE … condition with wildcards should be sufficient for simple cases. The interesting question will be how to scale this once you are dealing with much larger amounts of data, think YouTube for video portals. … Read more
You can store the target time in Mysql and you can fetch that target time in PHP and assign it to Javascript code, so the javascript will show the countdown timer. For countdown timer you can take any jquery script from here: http://www.tripwiremagazine.com/2012/11/jquery-countdown-scripts.html solved Count down timer in php with database [closed]
it is not working … the strings like />., still can be enter in the sql database It is working. mysql_real_escape_string is a function that escapes characters which have special meaning in SQL. / and > do not have special meaning in SQL, so it shouldn’t touch them. If they did have special meaning, then … Read more
I think you need to re-query res2 inside the outer loop, or at least reset the pointer. The second time through the outer loop you have nothing left in res2, since you’ve already reached the end In addition, with would be a lot more efficient if you setup the res2 query inside the outer loop … Read more
You are missing semicolons: if($ad==””){header(“location:index.php?kls=1″);}else {if($email==””){header(“location:index.php?kls=2″);}else {if($mesaj==””){header(“location:index.php?kls=3″);}else {if($kiriklink==””){header(“location:index.php?kls=4”);}else {mysql_query(“INSERT INTO bildirim (`ad`,`email`,`acklama`,`kiriklink`,`tarih`) VALUES (‘$ad’,’$email’,’$mesaj’,’$kiriklink’,now())”);header(“location:index.php?kls=5″);}}}} Btw. if you don’t use, then you should start using some IDE like netbeans or phpdesigner, it will show you where error is NEW CODE: if($ad==””){header(“location:index.php?kls=1″);}else {if($email==””){header(“location:index.php?kls=2″);}else {if($mesaj==””){header(“location:index.php?kls=3″);}else {if($kiriklink==””){header(“location:index.php?kls=4”);}else { $query = “INSERT INTO bildirim (`ad`,`email`,`acklama`,`kiriklink`,`tarih`) VALUES (‘$ad’,’$email’,’$mesaj’,’$kiriklink’,now())”; $result = mysql_query($query); … Read more
I think you need a query like this: select censusyear, sum(case CitycenGender when ‘Male’ then 1 else 0 end) as ‘Total Male’, sum(case CitycenGender when ‘Female’ then 1 else 0 end) as ‘Total Male’ from CitycenTable inner join CensusYearTable on CityCensusYear = CensusYearID Regards. 2 solved SELECT COUNT TROUBLE IN QUERY [closed]
SELECT * FROM table WHERE DATE(Registration Date and Time) = ‘2020-06-24’ DATE type format is YYYY-MM-DD check this link out as well, I think this is what you are looking for. 7 solved how to split mysql query condition
Don’t store images in your database, just store the references to them (file names or paths). If there will be more than one image per movie, then you will have a table representing this one-to-many relation: CREATE TABLE movie_images (movie_id int, image varchar(255)); For each image, insert a row: INSERT INTO movie_images (movie_id, image) VALUES … Read more
As MySql have YYYY-MM-DD HH:II:SS format you can achieve it using DateTime function of PHP as $date = DateTime::createFromFormat(‘d M Y H:i:s:u’, ’13 Sep 2014 00:35:23:440′); echo $date->format(‘Y-m-d H:i:s’); DEMO 1 solved PHP DateTime supported formats
Your SQL query/logic is completely wrong. What you should do is check if that user and password combination exits in database using WHERE clause. But actually you are doing is fetching each row and checking for equality. In such situation you can also get n numbers of wrong credentials. $query = mysql_query(“SELECT * FROM table … Read more
Replace your code with this . <?php try{ $db = mysqli_connect (‘localhost’, ‘root’, ”, ‘car_rental’) or die (“SQL is Off”); } catch (Exception $e){ echo “SQL is Off”; exit; } echo “success”; $email = $_POST[“email”]; $pass = $_POST[“pass”]; mysqli_select_db($db,”car_rental”); $result = mysqli_query($db,”SELECT email, users FROM users WHERE email =$email”); //$row = mysql_fetch_array($result); $row = $result->fetch_array(MYSQLI_ASSOC); … Read more
You are missing the connection parameter to sqlsrv_query. While you’re at it, you might as well use bind variables instead of string substitution to help guard against SQL-Injection attacks. $serverName = “serverName\instancename”; $connectionInfo = array( “Database”=>”dbName”, “UID”=>”username”, “PWD”=>”password” ); $conn = sqlsrv_connect( $serverName, $connectionInfo); $params = array($username, $password); $stmt = sqlsrv_query ($conn, ‘select * from … Read more
MySQL Community Server is free to download and use but isn’t supported. Enterprise version have support as you pay for this and other additional options. http://dev.mysql.com/downloads/mysql/ Also a bit more info here about using the free version in production, https://serverfault.com/questions/239978/is-the-community-mysql-safe-for-production-use solved I thought MySQL was free [closed]