[Solved] MYSQL How to perform custom month difference between two dates in MYSQL?

I think this query will do what you want. It uses (YEAR(CURDATE())*12+MONTH(CURDATE())) – (YEAR(STR_TO_DATE(join_date, ‘%d-%m-%Y’))*12+MONTH(STR_TO_DATE(join_date, ‘%d-%m-%Y’))) – – 1 to get the number of whole months of experience for the user, DAY(LAST_DAY(STR_TO_DATE(join_date, ‘%d-%m-%Y’))) – DAY(STR_TO_DATE(join_date, ‘%d-%m-%Y’)) + 1 to get the number of days in the first month, and DAY(CURDATE()) to get the number of … Read more

[Solved] Query database then email posts from where user is subbed to

I figured it out. Just use ob_start(), and loop through each user. Select the posts they’re subscribed to. Then inside the loop email it to each user. I used this query SELECT articles.* FROM articles INNER JOIN subscriptions ON articles.from_id = subscriptions.sub_to INNER JOIN users ON subscriptions.user_id = users.id WHERE users.email = :email 5 solved … Read more

[Solved] How to insert variable as a string into MySQL in Java

In general you can create strings with placeholders using: String result = String.format(“%s,%s”, v1, v2); If you are using JDBC, you can use a PreparedStatement, for example: PreparedStatement statement = connection.prepareStatement(“UPDATE table1 SET column1 = ? WHERE column2 = ?”); int i = 1; statement.setInt(i++, v1); statement.setInt(i++, v2); statement.executeUpdate(); For creating JDBC queries the PreparedStatement … Read more

[Solved] how to store and retrieve array in mysql [closed]

Looks like you’re using the php script to construct a sql statement. I do this all the time. Try something like: $galleryIds = implode(“,”,$galleries); $sql = “SELECT * FROM galleries WHERE id IN ($galleryIds)”; Cheers and please vote me up!! OK, Here’s an edit because it seems that the Stack thinks you’re going to use … Read more

[Solved] MySQL Joining a Table twice

SUM does not take two parameters like you did in sum(fleuge1.Preis,fleuge2.Preis) sum is an aggregate function , meant to sum all the values on a column, if you want to sum two values from a two distinct sets just do fleuge1.Preis+fleuge2.Preis if you want to post errors on stack overflow you can just copy them … Read more

[Solved] Join with multiple table

I believe here is what you looking for: SELECT SID, SNAME, count(DISTINCT PID) AS `c` FROM PRO_STU INNER JOIN Student USING (SID) GROUP BY SID, SNAME HAVING `c` = (SELECT count(*) FROM Professor) 1 solved Join with multiple table

[Solved] How to create and fill php array from Mysql database

RTM Example #1 Fetch all remaining rows in a result set <?php $sth = $dbh->prepare(“SELECT name, colour FROM fruit”); $sth->execute(); /* Fetch all of the remaining rows in the result set */ print(“Fetch all of the remaining rows in the result set:\n”); $result = $sth->fetchAll(); print_r($result); ?> 0 solved How to create and fill php … Read more

[Solved] storing user_id in session variable

Debug. Where do you store the value in the session state?: $_SESSION[‘user_ID’] = $userID; Ok, so where does $userID come from?: function selectUser($conn, $username, $password, $userID) { //… Ok, so where does the function parameter come from?: selectUser($conn,$username,$password) Nowhere. You never supplied a value to be stored in session, so no value was stored in … Read more