If the table was as follows (I’ve renamed user_id, post, and favorites columns to clarify their roles as I understand them) ————————————- |Users |posts |favorites | |———–|———–|———–| |id |id |id | |username |title |uid | |password |post_text |post_id | | |uid | | | |fav_id | | ————————————- This sql code can be used to … Read more
You need to place quotes around your date i.e. $timestring as “UPDATE posts SET creatdate=”$timestring” WHERE postid = 1 ” solved How can I set the MySQL date with string like 2015-07-30 18:32:18 [duplicate]
You have to count only owners id with DISTINCT word, which counts only unique owners. SELECT owners.city, count(DISTINCT owners.id) AS ‘Owners’ FROM owners INNER JOIN dogs ON (owners.id = dogs.owner_id) GROUP BY owners.city 1 solved Mysql Query [0001]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near at line 1 solved You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near at … Read more
If $row and $ar have an equal element count, I don’t see the reason for two loops. Your original code will do four iterations, and I’m not sure that’s what you want. (Judging by my uncertainty and the number of negative votes, you should probably update your question asap.) Code: (Demo) $arr=[’11’,’12’]; $ar=[‘1′,’2′,’3′,’4′,’5’]; // shuffle … Read more
Try This: <td><a href=”https://stackoverflow.com/questions/33755719/<?php echo $row[“image’]; ?>”>Hyperlink</a></td> Here I have given the link as the source of the hyperlink so that it directs to the link provided. 5 solved How to echo resulted data as hyperlink instead of plain data?
You can use this statement: SELECT id FROM st where name in (‘german’,’french’) Group by id having Count(*)=2 You should rename the column id in student_id solved Mysql query to find out which id is having both french and german
try something like this. $set = array( 7, 8 ); echo ‘<pre>’; foreach( $set as $number ){ //assuming number is your INT $array = range( 1, $number ); while( count( $array ) ){ echo “\n”; var_export( $array ); //remove first element array_shift( $array ); //remove last element array_pop($array); } } Outputs: For 7 array ( … Read more
The solution is to join on the common fields you already indentified: SELECT item_details.* FROM item_details JOIN item_detail_addon USING(Item_Details_Id) JOIN item_addon USING(Item_Addon_Id) If some fields on a table have the same name of a field on another table, you can get both by using aliases: SELECT table1.field1 as table1_field1 , table2.field1 as table2_field1 [ .. … Read more
Constructors don’t return values and you can’t just echo an object, try this instead. class some { private $my_string; public function __construct() { $this->my_string = ‘abc’; } public function test() { return $this->my_string; } } $some = new some; echo $some->test(); solved How can i access Return value throught the construct() from another function In … Read more
To use a resultset in a query condition for a set of queries you need a cursor. Please check out basics of cursor usage here and in the docs DELIMITER $$ CREATE PROCEDURE group_results_by_date BEGIN DECLARE v_finished INTEGER DEFAULT 0; DECLARE cdate DATE DEFAULT “2015-01-01”; — declare cursor for getting list of dates DEClARE date_cursor … Read more
To fill the form without reloading the page you will have to use Ajax to request the data from the server (database) and then fill it using javascript, i suggest reading about ajax functions with jquery. if you want for example to fill the id and click a button and the page will reload with … Read more
mysql query PHP: I want to a specific items to be first and can modify the query how many items to be displayed [duplicate] solved mysql query PHP: I want to a specific items to be first and can modify the query how many items to be displayed [duplicate]
I assume that ‘username’ is a text/char field in your db. Try this code: mysql_query (“SELECT * FROM ” . $iAccount_table . ” WHERE username=”” . $user . “””) or die(mysql_error()); I hope you find this helpful. solved MySQL error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL … Read more
Please try this code: $number = 0; $result = mysqli_query($con, $sql); if (!$result) exit(mysqli_error($con)); else $number = mysqli_num_rows($result); if ($number==0) { echo “No rented cars for this period !”; } else { while ($number){ $row = mysqli_fetch_row($result); $brand = $row[‘brand’]; $model = $row[‘model’]; $reg_num = $row[‘reg_num’]; $horse_powers = $row[‘horse_powers’]; $color = $row[‘color’]; echo $brand; $number–; … Read more