mysql

[Solved] How to make a link this is connected to database in php

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[ad_1] I agree with Marcosh (in the comments), so that would give you this code (between the if(…) { and } else): echo “<table><tr><th>ID</th><th>Name</th><th>Phone Number</th><th>Country</th><th>Email</th><th>Send SMS</th><th>Link to page</th></tr>”; // output data of each row while($row = $result->fetch_assoc()) { echo “<tr><td>” . $row[“id”]. “</td><td>” . $row[“firstname”]. ” ” . $row[“lastname”].”</td><td>” . $row[“phonenumber”]. “</td><td>” . $row[“city”]. ” … Read more

[Solved] explain command in mysql

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[ad_1] Basically explain is used to give you information regarding how the database goes about getting data using a query you specified. Typically you would use it if you have a slow query that you want to analyze. As far as I know, explains really only apply to statements that are doing data retrieval. So, … Read more

[Solved] SQL Error message: [closed]

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[ad_1] Hard to guess without as much details as needed, but i think you are escaping the values with aphostropes (‘). That’s php’s habit. MySQL doesn’t escape those values with aphostropes, it uses backtiks (`) or nothing. You could change your query part which you provided to remove those symbols: … 2013-12-10, NULL, dsffsd, dfsfsd, … Read more

[Solved] SQL query returns exception

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[ad_1] Looks like the value which should ALL .. compared to must be in front of ALL SELECT name, continent, population FROM world WHERE continent IN (SELECT continent FROM world x WHERE 25000000> ALL(SELECT population FROM world y WHERE x.continent = y.continent) ) [ad_2] solved SQL query returns exception

[Solved] filenames to mysql database [closed]

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[ad_1] Use PHP glob() function to get all files from a folder $files = glob(directory_path.”/*”); // get all files in a folder // Loop through array of fetched files and insert into database. foreach ($files as $file) { $filename = basename($file); // WRITE YOU MySQL code here that inserts filenames into DB } MySQL Insert … Read more

[Solved] Using mysql query and result in php? [closed]

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[ad_1] Your query looks fine. Use these statements to execute the query and get the count: $result = mysql_query($myquery); $rowCount = mysql_num_rows($result); If($rowCount !=0){ echo “NOT EMPTY”; }else{ echo “EMPTY”; } To FREE up the result: mysql_free_result($result); 2 [ad_2] solved Using mysql query and result in php? [closed]

[Solved] MYSQL: Search for User ID in one table to search for data in 2 other tables, then show data from all 3 tables

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[ad_1] SELECT * FROM section_user_map JOIN users USING (UID) JOIN verification USING (UID) WHERE SectionID = 65 AND CompleteDate BETWEEN ‘2012-05-09 12:00:00’ AND ‘2012-05-11 12:00:00’ See it on sqlfiddle. No UNION required. Outer join would only be required if you still want to return results for users who do not exist in one (or both) … Read more

[Solved] List ocurrences in column – SQL

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[ad_1] Based upon your question, it is a simple select distinct and then an order by SELECT distinct(Column_Name) FROM Table_name ORDER BY Column_Name DESC Or SELECT distinct(Column_Name) FROM Table_name ORDER BY Column_Name Depending on the Sort order that you want 4 [ad_2] solved List ocurrences in column – SQL

[Solved] How to create json response

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[ad_1] Try mysql_fetch_assoc: $json = array(); while ($row = mysql_fetch_assoc($result)) { $json[$row[‘uid’]] = array( ‘lat’ => $row[‘lat’], ‘lon’ => $row[‘lon’], ‘loc’ => $row[‘loc’] ); } echo json_encode($json); You should use MySQLi or PDO_MySQL instead of mysql_. 1 [ad_2] solved How to create json response

[Solved] Connection of JSP with MySQL failed

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[ad_1] Ok Here the Solution to connect MYSQL with JSP above given program. I asked about to my boss, he is a real expert… First open Netbeans Click on SERVICES then Right Click on the server like for me its “Apache Tomcat” then select Edit Server.XML Add below Line at line 39 i think between … Read more

[Solved] while loop inside an array

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[ad_1] You need to iterate through the results and add the values to your data array: $query = mysql_query(“SELECT * FROM tableName WHERE status=”confirm” ORDER BY datetime DESC “); $data = array(); while ($invoice = mysql_fetch_assoc($query)) { $data[] = array( ‘firstname’ => $invoice[‘firstname’], ‘lastname’ => $invoice[‘lastname’], ‘age’ => $invoice[‘age’], ); } mysql_fetch_assoc($query) returns only one … Read more