[Solved] You have an error in your SQL syntax…?

[ad_1] You will have to check if there is no starting and trailing comma’s in the $columns or $values variables. Plus, just to be sure, put appropriate quotes around the columns and values individually. public function insert($data, $table) { $columns = “”; $values = “”; foreach ($data as $column=>$value) { $columns .= “`” . $column … Read more

[Solved] MS SQL query not working on MySQL [closed]

[ad_1] SELECT ppmap_d.*, p_prob.*, ppmap_h.*, p_probgroup.*, p_prod.*, ppmap_d.prob_id AS probid, ppmap_d.map_id AS mapid, ppmap_h.pg_name AS probgname, ppmap_h.m_id AS modelid FROM p_prob INNER JOIN p_prod ON ppmap_d.prob_id = p_probgroup.prob_id INNER JOIN ppmap_h ON ppmap_h.map_id = ppmap_d.map_id AND ppmap_h.pg_name = p_probgroup.pg_name INNER JOIN ppmap_d ON p_prod.m_id = ppmap_h.m_id INNER JOIN p_probgroup ON p_prob.prob_id = p_probgroup.prob_id; 4 [ad_2] … Read more

[Solved] PHP script to update mySQL database

[ad_1] Your sql is wrong. Apart from the gaping wide open SQL injection attack vulnerability, you’re generating bad sql. e.g. consider submitting “Fred” as the first name: $First_Name2 = “Fred”; $query = “UPDATE people SET Fred = First_name WHERE ….”; now you’re telling the db to update a field name “Fred” to the value in … Read more

[Solved] Auto refresh PHP script backend [closed]

[ad_1] To refresh a page without reloading, you have to load the contents of the page through ajax. You could do this as follows: index.php <html> <head> <script type=”text/javascript”> $(document).on(‘ready’, function(){ setInterval(function() { $.ajax({ type: “GET”, url: “ajax_refresh.php”, success: function(result) { $(‘body’).html($result); } }); }, 3000); }); </script> </head> <body> <div class=”header”> Header of website … Read more

[Solved] Simplify SQL query for me please [closed]

[ad_1] I am not sure if I got your question all clear, this query below will give you the latest employee record if there are multiple user records – SELECT * FROM employmentrecords WHERE id IN(SELECT MAX(id) FROM employmentrecords WHERE ((date_end >=’2017-08-22′ OR date_end IS NULL OR (date_end <=’2017-08-22′ AND date_end >=’2017-08-08′)) AND date_hired <=’2017-08-22′) … Read more

[Solved] where conditon to get date in two columns familyno and date

[ad_1] General Format, query =select * from table_name where table_col1=”+getvalue1()+” && table_col2=”+getvalue2()+”; in order your database, query=”select * from userVO where familyno=”+udto.getFamilyno()+” && date=”+udto.getDate()+”;”; 2 [ad_2] solved where conditon to get date in two columns familyno and date

[Solved] A Parse error with the PHP mysql Class function of insert method

[ad_1] This line of code isn’t closed: $this->query(“INSERT INTO testing_Rand (number1, // etc and you are missing a ; after this line: $newRand.=implode(‘,’, $varNum) If I get it, you meant to write this instead: public function insert_SQL($varNum ) { $this->query(“INSERT INTO testing_Rand (number1, number2, number3, number4, number5, number6, number7, number8, number9, number10) VALUES (“.implode(‘,’, $varNum).”)”); … Read more

[Solved] Why mysql_num_row less than condition doesn’t work?

[ad_1] Use this: <?php $sql=mysql_query(“SELECT ID FROM emp WHERE user=”$login_session””); // its currently zero $row=mysql_num_rows($sql); $b = 3; $tot=$b – $row; echo “$tot”; if($row < $b) { echo “good”; } else { echo “wrong”; } ?> You have been trying to output variables, which is not defined. You code was: Ouput undefined variables Assign something … Read more

[Solved] How to store and display an image in MySQL database

[ad_1] Well, you gave a different name for the file in the input file tag in your form. Change this <input type=”file” name=”image” ><br> to this <input type=”file” name=”file” ><br> and it should work. Let me know if it doesn’t. You may also consider putting the contents in upload_file.php in an if-conditional to prevent it … Read more

[Solved] mySQL data type for form elements

[ad_1] 1) you will get string as the value of radio so it will be varchar type 2) for check boxes any one can have multiple values so you need to create a separate table(working_project) for this values( data type will be same as radio) and another table for mapping(user_working_project) user_working_project table will containing user … Read more

[Solved] Relation to many and get without this

[ad_1] In SQL, this type of query needs what is known as an EXCEPTION JOIN. Some RDBMSs actually implement this as a separate type (such as DB2), while others need to use a workaround. In your case, it amounts to (in SQL): SELECT User.* FROM User LEFT JOIN UserHouse ON UserHouse.id_user = User.id WHERE UserHouse.id_user … Read more