[ad_1] You can do aggregation with coalesce() : select event_id, coalesce(max(case when state=”FAILED” then ‘FAILED’ end), max(case when state=”COMPLETED” then ‘COMPLETED’ end), ‘PENDING’ ) from table t group by event_id; [ad_2] solved Very complicated SQL query
[ad_1] All of your name‘s for inputs are the same, so it only can see one of them, it doesn’t know the difference between “mark” and “mark” and “mark” etc. Add different id’s to them, like “mark1” etc. Then in your php, MAKE SURE TO SANITISE THE INPUTS!! or else people can use sql injection … Read more
[ad_1] use JSON_ENCODE first before saving the array to DB ,then use JSON_DECODE if you want to get again the contents $arr = array( “item_number1” => “1”, “payment_date” => “04:21:34 Dec 06, 2014 PST”, “payment_status” => “Completed”, “first_name” => “sdfsd”, “last_name” => “parsdfsdandekar”, “quantity1” => “1” ); echo json_encode($arr); Result after JSON_ENCODE (Array to JSON … Read more
[ad_1] Solution for your problem is to use PIVOT Try to look at this: Convert Rows to columns using ‘Pivot’ in SQL Server 4 [ad_2] solved dynamic query to column to row in mysql [closed]
[ad_1] In your __construct seem you don’t call the proper function sequence for format (htlm) the row. I think you should change you __construct someway for call beginChildren, current, endChildern properly function __construct($it) { beginChildren(); parent::__construct($it, self::LEAVES_ONLY); current(); endChildren(); } [ad_2] solved show sql results in php with tables [closed]
[ad_1] It creates a new table “students” in the database if it doesn’t exist already. Each row from ” student_id” to “Reg_date” represent one column in the table. NOT NULL next to a column means you can’t leave it empty when you insert data. “student_id” is a primary key, and is automatically incremented for each … Read more
[ad_1] Try adding white spaces between your query words and make sure you escape the input: $id = mysql_real_escape_string($id); $str = mysql_real_escape_string($str); $name = mysql_real_escape_string($name); $r=mysql_query(“INSERT INTO varta (id,data,name) VALUES (‘$id’,’$str’,’$name’);”); Or better yet – take a look at MySQLi or PDO and use prepared statements. [ad_2] solved Is my SQL syntax really wrong? [closed]
[ad_1] Follow the examples provided in PHP the Right Way under password hashing: require ‘password.php’; $passwordHash = password_hash(‘secret-password’, PASSWORD_DEFAULT); if (password_verify(‘bad-password’, $passwordHash)) { // Correct Password } else { // Wrong password } DO NOT under any circumstances “invent” your own algorithm. These are notoriously tricky to get right and unless you have a background … Read more
[ad_1] For example… DROP TABLE IF EXISTS my_table; CREATE TABLE my_table (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,date DATE NOT NULL ,price INT NOT NULL ); INSERT INTO my_table VALUES (1 ,’2014-01-01′, 10), (2 ,’2014-01-02′, 10), (3 ,’2014-01-03′, 10), (4 ,’2014-01-04′, 10), (5 ,’2014-01-05′, 20), (6 ,’2014-01-06′, 20), (7 ,’2014-01-07′, 10), (8 ,’2014-01-08′, 10); … Read more
[ad_1] For a start, JavaScript is code that a user can actually edit using DOM tools (like inspect element) and should never be used as a mechanism to security with Databases. You should firstly start to research about prepare statements in PDO if you’re using un-trusted user input; the bind paramtter in the PDO interface … Read more
[ad_1] You can make something like this: $postID = 1;//Post id we want to get from the database $getPost = $connection->query(“SELECT * FROM posts WHERE post_id=’$postID'”);//Get the post by the id $post = $getPost->fetch_assoc();//Fetch the result to an array $getUser = $connection->query(“SELECT username FROM users WHERE user_id=”.$post[‘id’]);//Get the username by using the id we got … Read more
[ad_1] I’d recommend you split the String in a separate step prior to the iteration. Also, validate that you really do receive the expected parameter from the HTTP request in the first place. [ad_2] solved JavaEE, Jboss, Empty string somewhere [closed]
[ad_1] Far and away the best solution is to redesign your schema to store each part of notenumber in a different field. Barring this, you need to split out each part of notenumber, convert it to a numeric type, and order by it. You’ll have to add a clause to the order by for each … Read more
[ad_1] There are many things to solve the problem. Let me show you one of them by using MySQL procedures. Steps are as follows: 1°) create a procedure that generates an identifier for a table (generate_id) 2°) create a procedure that inserts the data into the table (insert_users) by using the first procedure (generate_id) to … Read more
[ad_1] Just some suggestions: Firstly, it’s good practise to enclose the values of tag attributes in quotes. For instance: echo “<div id=swap>”; becomes echo “<div id=’swap’>”; 1 [ad_2] solved php div content swap – how to include in echo command [closed]