[Solved] MySQL INSERT statement brings an error [closed]

Order is reserved word in MySQL, you can use back tick(`) around table name Also you can use MySQL NOW() function for date instead of PHP variable $date $t = “INSERT INTO `order` (order_date) VALUES (NOW())”; solved MySQL INSERT statement brings an error [closed]

[Solved] convert sql server file into mysql [closed]

The constraint lines in you output may define the constraints, eg: ALTER TABLE [dbo].[Message] WITH CHECK ADD CONSTRAINT [FK_Message_Message] FOREIGN KEY([OpratorID]) REFERENCES [dbo].[Oprator] ([ID]) says there is a relationship between Message and Operator ( Message.OperatorID = Operator.ID ) 0 solved convert sql server file into mysql [closed]

[Solved] How to use PHP in a html5 setting [closed]

This is missing an ending div tag. And the first div is missing an equal sign. <article> <div class”content_container”> <div class=”content_loading_container”></div> </article> It needs to be this… <article> <div class=”content_container”> <div class=”content_loading_container”></div> </div> </article> That’s the only remaining syntax error that I can see. Now you say ur adding these php pages and when you … Read more

[Solved] simple PHP to MYsql filtering

As I understand you receive plain text emails with data. Then you want to parse it. If your ‘labels’ are automatically generated and consistent then you can parse it quite easily… say something like this: Say you load your email text into a variable $email_content. $lines = explode(“\n”,$email_content); $array_of_values = array(); foreach ($lines as $line) … Read more

[Solved] MySQL: Return 2 different result together

SELECT qe.id, qe.content, a.id, a.content, a.dt, acr.checked, acr.score FROM `questions_and_exercises` qe, `questions from-to` qft LEFT JOIN `questions-answers` qa ON (qa.qid=q.id AND qa.uid=?) LEFT JOIN answers a ON (a.id=qa.aid) AND qft.to_lid=? AND qft.uid=? 2 solved MySQL: Return 2 different result together

[Solved] sql query not executing on local host

after you sort out the connection you might want to fix your table echo “<table border=”1″>”; while($row=mysqli_fetch_array($result)){ $col_name = $row[‘Field’]; $click = “<a href=”https://stackoverflow.com/questions/43335024/Column_details.php?mv=”.$col_name.””>” .$col_name. “</a>”; echo “<tr>”; echo “<td>” . $col_name . “</td>”; echo “<td>” . $click . “</td>”; } echo “</table>”; 4 solved sql query not executing on local host

[Solved] how to put value in buttons? [closed]

So this is very crude, but it is one way you can do what you are trying to do: <table> <?php while($row=mysql_fetch_array($check2)) { ?> <tr> <td><?php echo $row[‘wTitle’]; ?></td> <td>Click to edit</td> </tr> <tr> <td style=”text-align:right;”><?php echo $row[‘wContent’]; ?></td> </tr> <tr> <td colspan=”2″ height=”202″>&nbsp;</td> </tr> <tr> <td colspan=”2″> <form action=”view.php” method=”post”> <input type=”submit” name=”submit” value=”edit” … Read more

[Solved] Joining multiple tables in one

By means of this, I was able to analyze that serial used in SO is different/same as used in DR. To match so entries with dr entries you can join table b twice, first time take ‘so’ entries then second time take ‘dr’ entries. So you will get “header”, “SoEntry”, “DrEntry”. Then you can compare … Read more

[Solved] How to do i create a unique page for each row in database with PHP?

You could try something like this to generate “different” page using one file only(example.com/title.php) Loop through your database to get all data while creating a <a> for each of them: foreach ($retrieveResult as $result) { echo ‘<a href=”https://stackoverflow.com/questions/44427393/example.com/title.php?name=”.$result[“title’].'”>’.$result[‘title’].'</a>’; } This will generate something like this: <a href=”https://stackoverflow.com/questions/44427393/example.com/title.php?name=titleA”>titleA</a> <a href=”example.com/title.php?name=titleB”>titleB</a> <a href=”example.com/title.php?name=titleC”>titleC</a> <a href=”example.com/title.php?name=titleD”>titleD</a> To get … Read more

[Solved] Radio Button not working [closed]

This line is missing a comma: $Query .= “banner_images=””.$banner_images.”””; should be $Query .= “banner_images=””.$banner_images.””,”; As a sidenote, you are vulnerable to sql injection with your code, you might want to use prepared statements or at least mysql_real_escape_string 3 solved Radio Button not working [closed]

[Solved] Mysql java taking registration [closed]

Follow the steps: 1. Download Mysql and Install+ dwnload mysql-connector jar file. 2. in the mysql(u can connect using mysql command line client) provide ur pwd and get ready. Put below code: 3. create database TEST 4. use TEST. 5. CREATE TABLE USER_DTLS (USERNAME VARCHAR2(100), PASS VARCHAR2(100)); creating tables 6. INSERT INTO USER_DTLS(‘user1’, ‘user1234’);INSERT INTO … Read more