Both your PHP and your MySQL syntax have problems. First, your SQL statement needs to be surrounded by quotes. Secondly, the syntax for LOAD DATA INFILE is incorrect. Try this: $stmt=$db->prepare(“LOAD DATA INFILE ‘insert.txt’ into table `Info`”); $stmt->execute(); See the MySQL docs for LOAD DATA INFILE for more options. You’ll probably need to specify your … Read more
You forgot to put the field name before “NOT IN” : SELECT * FROM users WHERE username IN (‘aniket27′,’deepakrajak’,’bhawana’,’Mehul13′,’sanchayeeta’,’shivajidutta’,’anamika_4a’,’parekh’,’anupamkumar’) AND username NOT IN (‘aniket27’) ORDER BY id DESC LIMIT 2 solved How to use IN & NOT IN same query [closed]
Applications which runs on the end-users machines should never-ever have direct database access. Create a REST API with PHP (if you already using it) which handles the database operations and invoke it with JavaScript (this is the short explanation of AJAX). solved INSERT into MySQL database with JavaScript but without Node.js [closed]
With java.sql.Time you retrieve the right value from your time field in mysql. import java.io.IOException; import java.sql.Time; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; public class teste { /** * @param args * @throws IOException */ public static void main(final String[] args) throws IOException { SimpleDateFormat sdf = new SimpleDateFormat(“HH:mm:ss”); try { Date data = sdf.parse(“21:00:00”); … Read more
You can use DISTINCT to achieve it. Syntax: SELECT DISTINCT column_name FROM table_name; Based on above syntax, your query should be SELECT DISTINCT CLASS FROM ‘table_name’ solved Retrieve table values without retrieving duplicate values [closed]
SQL databases play little role in data mining. (That is, unless you consider computing various business reports involving averages as “data mining”, IMHO these should at most be called “business analytics”). The reason is that the advanced statistics performed for data mining can’t be accelerated by the database indexes. And usually, they also take much … Read more
If you are looking for an update statement that you would run periodically, and that sets the status of newly expired items, that would be: update orders set status=”expired” where curent_date > expired_date and status=”new” On the other hand… In your schema, status is a derived information, that is a column whose value can be … Read more
To get the last 3 characters: $string = “2.5 lakh videos views 0.8″; $valSubstr = substr($string, -3); echo $valSubstr; To get the last “part” of the sentence. (this way you don’t have to care about the count of characters in your number) $string = “2.5 lakh videos views 0.8”; $partsString = explode(‘ ‘, $string); $valExplode … Read more
Missing Comma (,) in this line. Due to which bound variables were not matching. $req = $pdo->prepare(“INSERT INTO t_events_changes …. Values (… :new_standby_start:old_standby_end, … )”); ^ here missing comma Change it to, :new_standby_start,:old_standby_end, 2 solved Cant solve this : Invalid parameter number: number of bound variables does not match [closed]
You can use the MAX() and MIN() function to get the ids having largest and the id having smallest discount. Select id,discount from customer where discount=(select MAX(discount) from customer) OR discount=(select MIN(discount) from customer); 3 solved select id by the min and max (sql) [closed]
The only difference is that the first query will return a row for each pair of rows in the table where P1.att2 > P2.att2 and P2.att1 = x, while the second query will just return one row for each row in the table where att2 is greater than in some row where att1 = x. … Read more
Error: you have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use solved Error: you have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use
The error is coming from this line: $sql1 = mysql_query($sql_1) or die(mysql_error()); $sql_1 is not a query, it’s the return value from another call to mysql_query. $sql_1 = mysql_query(“insert into `student_invoice` set ProfileID = ‘”.$_SESSION[“stud_id”].”‘ , Inv_No = ‘”.$today = date(“M-Y”).”-“.$checkvalu.”‘, Inv_Date=””.$_POST[“TXNDATE”].””, Inv_Order=””.$_POST[“ORDERID”].”” “) or die(mysql_error()); Remove this line from the script: $sql1 = mysql_query($sql_1) … Read more
I’m answering this because it’s non-trivial and because I want to see if I can actually do it :p SELECT `ID_PLAYER`, COUNT(*) AS `MATCH_WIN` FROM (SELECT IF(`SCORE_PLAYER1`>`SCORE_PLAYER2`, `ID_PLAYER1`, `ID_PLAYER2`) AS `ID_PLAYER` FROM `your_table_name_here` ) AS `tmp` GROUP BY `ID_PLAYER` 3 solved Mysql team/score [closed]
You won’t be able to write directly to the database from JavaScript. You’ll have to send the data back to the server (presumably using the submission of the sign-up form) and, in the server-side form handler, you can store the value in the database. A full implementation is beyond the scope of a simple question … Read more