[Solved] Get value using data [closed]
Your are trying to get attribute, use attr() for it with complete name of attribute: var name = “data-cityid”; alert($(“#myid”).attr(name)); Here is demo 1 solved Get value using data [closed]
javascript
[Solved] How to translate a ‘greeting_for’ function from Ruby to Javascript [closed]
It can be translated to JavaScript as: function greeting_for (name) { return `Hello, ${name}!` } console.log( greeting_for( “Marty” ) ) 2 solved How to translate a ‘greeting_for’ function from Ruby to Javascript [closed]
[Solved] What is the $$ function in JavaScript? [closed]
If you are in Chrome, it provides $$ in the console by default as a wrapper around doing document.querySelectorAll(…) $$ on it’s own however is not any special value, it entirely depends on the system running the javascript. solved What is the $$ function in JavaScript? [closed]
[Solved] Passing string variable in Javascript
Sure you can. You just need to add quotes. function test(test1) { console.log(typeof test1); } document.write(“<input type=”button” value=”Click” id=’j’ onclick=’test(\”abc\”)’/>”); solved Passing string variable in Javascript
[Solved] jQuery doesn’t give a proper output, but gives these [closed]
You’re trying to use title1 before it’s defined. swap the lines var title1 = $(‘#node-264152’).find(‘.audio-description’).html(); var linkText = document.createTextNode(title1); Should be noted that since you’re already using jQuery, you could do var title1 = $(‘#node-264152’).find(‘.audio-description’).html(); $(‘<a />’, { href : ‘http://www.someprivatelink.net’, title : title1, text : title1 }).appendTo(‘body’); 1 solved jQuery doesn’t give a proper … Read more
[Solved] First child does not work with my selector
That is because first-child(2) is not a function so it will give an error. It should be: $(‘dd:first-child, dd:eq(1)’).remove(); or $(‘dd:eq(0), dd:eq(1)’).remove(); or $(‘dd:nth-child(1), dd:nth-child(2)’).remove(); This might also work: $(‘dd:lt(2)’).remove(); lt selector Fiddle for lt(2) Edit: To delete the <br> you can do: $(‘dd br:lt(2)’).remove(); 3 solved First child does not work with my selector
[Solved] Group checkboxes in JSFiddle: Part2 [closed]
Register a callback which will check whether all the checkboxes in the current group is checked or not $(‘input[id^=checkall]’).click(function(){ $(this).closest(‘fieldset’).find(‘input’).not(this).prop(‘checked’,this.checked); }); $(‘:checkbox’).not(‘[id^=checkall]’).click(function(){ var all = $(this).closest(‘fieldset’).find(‘[id^=checkall]’); var chks = $(this).closest(‘fieldset’).find(‘input’).not(all); all.prop(‘checked’, chks.length == chks.filter(‘:checked’).length); }) Demo: Fiddle solved Group checkboxes in JSFiddle: Part2 [closed]
[Solved] how to store new elements added in webpage by user? [closed]
You can use JavaScript to set a cookie with all the changes you want to keep. If the user returns to the page later, restore the changes from the cookie. 1 solved how to store new elements added in webpage by user? [closed]
[Solved] Creating a account system that runs on every computer js [closed]
Try using a database like MongoDB or MySQL. Push variables to the DB and Pull them down as necessary. These systems can be run on your local machine. Local storage is not sufficient for what you are attempting. solved Creating a account system that runs on every computer js [closed]
[Solved] Sort bullit list by li class [closed]
use .unwrap() and .wrapAll(): $(‘ul li’).unwrap(); $(‘.a’).wrapAll(‘<ul></ul>’) $(‘.b’).wrapAll(‘<ul></ul>’) $(‘.c’).wrapAll(‘<ul></ul>’) Demo 5 solved Sort bullit list by li class [closed]
[Solved] Simple way of creating jQuery Slider
Today I tried a content slider, with fixed pagination. I implemented this for something, which I would say after it is released. I could have simply used a plug-in, but due to some technical issues, and I too wanted to learn something, so I did it on my onw. I started with the HTML Markup, … Read more
[Solved] Find and remove all non numbers from array in JavaScript w/out JQuery
Array.splice is useful here. I’m sure this solution can be optimized. array.forEach((item, index) => typeof item !== ‘number’ && array.splice(index, 1)); 6 solved Find and remove all non numbers from array in JavaScript w/out JQuery
[Solved] $.on(“click”, function() | does not click. Element is dynamically generated [duplicate]
Use event delegation: $(document).on(‘click’, ‘.edit’, function(){ //function to edit tasks alert(“The check was clicked.”); }); var c = $(‘#c’); $(‘#add’).on(‘click’, function(){ c.append(‘<span class=”edit”><i class=”fa fa-pencil” aria-hidden=”true”></i> Hello</span>’); }); $(document).on(‘click’, ‘.edit’, function(){ //function to edit tasks alert(“The check was clicked.”); }); div { margin-top:10px; } .edit { width:25px; height:25px; margin: 0px 10px 10px 0px; background:#000; color:#fff; … Read more
[Solved] How to get numbers in a string separated with commas and save each of them in an Array in Javascript [duplicate]
use split & map & parseInt methods. var numbers=”15,14,12,13″; var result=numbers.split(‘,’).map(function(number){ return parseInt(number); }); console.log(‘convert ‘+JSON.stringify(numbers)+” to array:”+JSON.stringify(result)); Use eval method var numbers=”15,14,12,13″; var result=eval(“[“+numbers+”]”); console.log(‘convert ‘+JSON.stringify(numbers)+” to array:”+JSON.stringify(result)); solved How to get numbers in a string separated with commas and save each of them in an Array in Javascript [duplicate]
[Solved] ruby on rails 4/jquery/javascript: button only works after page reload
Line 433 of http://new.mapmill.org:3000/assets/sites.js $(‘#upload_more’).click(function() { return window.location.href=”https://stackoverflow.com/sites/” + $(‘#site_id’).val() + “/upload”; }); You are binding the event handler on DOM ready, but your page content is loaded dynamically. So at the time you binding the event, $(‘#upload_more’) doesn’t even exist in the DOM. In my experences this is commonly happened when someone is developing … Read more