[ad_1] Basic regular expression /^[+-]\d+\.\d+$/ Explanation: ^ Match start of string [+-] Match either plus or minus \d+ Match one or more numbers of digits \. Match a period, the \ escapes it since it means any character \d+ Match one or more numbers of digits $ Match end of string 1 [ad_2] solved JavaScript … Read more
[ad_1] It all starts from function start() at the bottom. For displaying purpose i’ve used a small dataset but you can require the data from the json file by using const data = require(‘data.json’). I’ve tested for large dataset also, works like a charm. Hope it helps. const data = { “United States”:[ “Washington”,”Bratislava”,”Hard”,”Going”], “Afghanistan”: … Read more
[ad_1] You could reduce the array and check if the previous value is equal to the actual value. function sumSame(arrayA, arrayB) { var i, l = arrayA.length, resultA = [], resultB = []; for (i = 0; i < l; i++) { if (arrayA[i] === arrayA[i – 1]) { resultB[resultB.length – 1] += arrayB[i]; } … Read more
[ad_1] The JavaScript runtime is a single-threaded environment – – that is, it executes a single command at a time (synchronous). However, the browser that hosts the JavaScript runtime runs in a multi-threaded environment (the operating system). This means that while the JavaScript runtime can only process one line of code at a time, the … Read more
[ad_1] TL/DR: Yes. If not, it’s likely your own fault. But there are a few easy fixes for when an OL application becomes slow/unresponsive. Use the image render mode(previously known as ImageVector) for large vector layers. ol.layer.Vector({ renderMode: ‘image’, … }) Great performance, but point symbols and texts are always rotated with the view and … Read more
[ad_1] I think you are looking for this : confirm(“I.AM.READY!”); var age=18; age = prompt(“What’s your age?”); if (+age>=18) { console.log(“You can play”); } else { console.log(“we take no responsibilty”); } console.log(param); , takes the below as parameters : obj1 … objN : A list of JavaScript objects to output. The string representations of each … Read more
[ad_1] Classes are usually Capitalized, everything else is usually camelCased. [ad_2] solved Naming guidelines for JavaScript [closed]
[ad_1] a << b = a · 2b a >> b = a / 2b = a · 2-b (dropping any decimals) So to calculate 4 << 5, you need to double 4 five times: 4 · 25 = 4 · 32 = 128. Similarly for 3 >> 3. 4 [ad_2] solved Bitwise Left shift … Read more
[ad_1] David here, from the Zapier Platform team. I’m glad you’re showing interest in the code step. Assuming your assumptions (32 characters exactly) is always going to be true, this should be fairly straightforward. First off, the regex. We want to look for a character that’s a letter, number, or punctuation. Luckily, javascript’s \w is … Read more
[ad_1] it’s sample on w3schools You can try it. <!DOCTYPE html> <html> <body> <p>This example uses the HTML DOM to assign an “onclick” event to a p element.</p> <p id=”demo”>Click me.</p> <script> document.getElementById(“demo”).onclick = myFunction(); function myFunction() { //your codes here Zean document.getElementById(“demo”).innerHTML = “YOU CLICKED ME!”; } </script> </body> </html> [ad_2] solved The JavaScript … Read more
[ad_1] An approach should consider breaking the OP’s entire task into two separate ones. Within an intermediate step one firstly does reduce the list of material items into a map of (grouped) material items. The final step does a map–reduce on the values of the intermediate result, where the reduce task is responsible for summing … Read more
[ad_1] Just try like this function img_find() { var imgs = document.getElementsByTagName(“img”); var imgSrcs = []; for (var i = 0; i < imgs.length; i++) { imgSrcs.push(imgs[i].src); } return imgSrcs; } [ad_2] solved Get the src value from the img tag [closed]
[ad_1] Try this: var emailpat = /^[^@]+@[^@]+\.[^@\.]{2,}$/; Email addresses should have just one @-sign, and that can’t be the first character. After the @ you’ll need at least one dot followed by 2 or more letters. And yes, this also accepts email addresses that are not valid. If you want to be sure that the … Read more
[ad_1] Using Flexbox, you can use order. .container{ display:flex; } .order-1{ order:1; } .order-2{ order:2; } .order-3{ order:3; } @media(min-width:992px){ .order-lg-1{ order:1; } .order-lg-2{ order:2; } .order-lg-3{ order:3; } } <div class=”container”> <div class=”order-3 order-lg-2″>A</div> <div class=”order-2 order-lg-1″>B</div> <div class=”order-1 order-lg-3″>C</div> </div> 0 [ad_2] solved How to change order of elements when device is mobile … Read more
[ad_1] If your array-of-arrays only has one level, then you can just map it like this: var filtered = array.map(subarray => subarray.filter(el => el != null)); console.log(filtered); 1 [ad_2] solved How to remove null values from nested arrays