java

[Solved] Error “no such element: Unable to locate element”

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The email field is inside the frame. Before access any element in the frame, you have to switch. please try following code. public static WebElement Email_Field(WebDriver driver) throws InterruptedException { WebElement element; (new WebDriverWait(driver, 30)).until(ExpectedConditions.frameToBeAvailableAndSwitchToIt(“alibaba-login-box”)); element = driver.findElement(By.xpath(“//input[@id=’fm-login-id’]”)); while (!isDisplayed(element)) { Thread.sleep(3000); System.out.println(“Element is not visible yet”); } return element; } solved Error “no such … Read more

[Solved] Can Java delimit input itself, without explicit delimiters?

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Assuming you’re using scanner, yes, it could. The scanner operates on the notion that a regexp serves as delimiter: Each match of the regex delimits, and whatever the regexp matches is tossed out (because nobody ‘cares’ about reading the spaces or the commas or whatever). The scanner then gives you stuff in between the delimiters. … Read more

[Solved] Asking the user for a URL to receive a JSON

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Create a constructor in your async Task private class JSONTask extends AsyncTask<String, String, String> { String url; public JSONTask(String url){ this.url=url; } use the url string in place of params[0] And wherever you call your async task do it like this new JSONTask(textView.getText()).execute() This should solve it. Else you can directly use the do in … Read more

[Solved] Java Switch Statement for operators

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Try out this : package com.sujit; import java.util.Scanner; public class UserInput { public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean flag = true; do { System.out.println(“Enter 1st number”); int num1 = input.nextInt(); System.out.println(“Enter 2nd number”); int num2 = input.nextInt(); System.out.println(“select one operator :\n 1)+\n2)-\n3)*\n4)/\n5)Exit(Enter E)\n”); System.out.println(“Enter your choice :”); char choice … Read more

[Solved] My android application is getting stopped

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Go to the your Manifest file and do this in the activity where you want to show the Toolbar <activity android:name=”.YourActivity” android:theme=”@style/AppTheme.NoActionBar”><!– ADD THIS LINE –> Then in styles.xml add the following: <style name=”AppTheme.NoActionBar”> <item name=”windowActionBar”>false</item> <item name=”windowNoTitle”>true</item> </style> solved My android application is getting stopped

[Solved] What does it mean by Object [ ] [closed]

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your generateNewGreedySolution method returns an array of Object Type In the 5th line you are doing Object[] values = new Object[ins.getDimension()]; So here values is an object array and hence you are returing the same. If you are confused of what to return in methods then please note that if your method signaure is int … Read more

[Solved] How to make a text change you from one screen to another [closed]

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I suppose you are referring to changing from one screen (activity) to another by typing something and not by clicking a button. If that is the case use TextWatcher and on change check for your string (or command) and move to next screen. Something like. textView.addTextChangedListener(new TextWatcher(){ public void afterTextChanged(Editable s) {} public void beforeTextChanged(CharSequence … Read more

[Solved] java convert a english letter to unicode [closed]

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It doesn’t work because .next() returns a String. Instead, read the first character of the string returned. Scanner input = new Scanner(System.in); String temp = input.nextLine(); char ch = temp.charAt(0); int a = (int) ch; System.out.println(a); 0 solved java convert a english letter to unicode [closed]

[Solved] Java – how do I iterate through this map so method my method returns a string [closed]

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A loop won’t return the String you want this way, you need to create the String and, at every loop, concatenate a new one to it: public static String m(Map<String, String> mp) { Iterator<?> it = mp.entrySet().iterator(); String str = “{” + ” \”SomeAttribute\”: ” + “{“; while (it.hasNext()) { Map.Entry pair = (Map.Entry) it.next(); … Read more

[Solved] how do I initialize 0 to both constructors? [closed]

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Your code is correct for your teacher’s requirements so far. Constructors effectively create an Object. In this case you have 2 constructors VendingMachine() and VendingMachine(int cans) both of which in their respective code initialize tokenCount to 0. Walking through your Tester line by line VendingMachine machine = new VendingMachine(); This constructor creates a new VendingMachine … Read more