You have declared: public double MaxKiv() { So yes, obviously this gives you a double. To get an int instead, simply change the declaration to return an int: public int MaxKiv() { The value you are returning, index, is already declared an int, so this should be enough fix your issue. 0 solved How to … Read more
You can use the static method: String.valueOf(number) Or new Integer(number).toString(); 1 solved How do I store a int in a String? [duplicate]
In your case Boy IS-A Human, so you can create Human, with Boy’s constructor. But since (as per OOP) Human is not a Boy, thus you cannot create Boy’s instance calling the Human’s constructor. So you cannot create a child instance directly using the super or parent constructor. Boy boy = new Human(); NOT POSSIBLE … Read more
more is a unix command to display the contents of a file, paginated. It has nothing to do with Java. solved more syntax in Java [closed]
In C, double has at least as much precision as, and usually more than, float, and has at least the exponent range of, and usually more than, float. The C standard only requires that double be able to represent all the values of float: “The set of values of the type float is a subset … Read more
The most likely explanation is that you have a bug in your Java application that is causing it to leak file open files. The way to avoid the problem is to write your code so that file handles are always closed; e.g. // Using the ‘try with resource’ construct try (Reader r = new FileReader(…)) … Read more
This should do it. What it does is that it gets a string to look at, gets a character to look at, iterates through the string looking for matches, counts the number of matches, and then returns the information. There are more elegant ways to do this (for example, using a regex matcher would also … Read more
Maybe what you actually want is to use a Predicate? Predicate<Integer> crazyFunction = x -> false; for (Integer thisInteger : listOfIntegers) { crazyFunction = crazyFunction.or(Predicate.isEqual(thisInteger)); } // Is a given integer one of our integers? boolean isGoodInteger = crazyFunction.apply(42); 2 solved How can I change one function value in a boolean-valued java Function?
Why int[] aa={’12’,’2′}; is invalid and int[] aa={‘1′,’2’}; is valid? error showing is Invalid character constant [closed] solved Why int[] aa={’12’,’2′}; is invalid and int[] aa={‘1′,’2’}; is valid? error showing is Invalid character constant [closed]
Just use comparator, an example of sorting by firstName then by lastName list.forEach(l -> l.sort(Comparator.comparing(CsvEntity::getFirstName) .thenComparing(CsvEntity::getLastName))); Of course you have to have getters for your fields to use method reference solved how sort in java8 list of lists of object by multiple properties [duplicate]
Your calculation is effectively canceling: 3 + 3 * -1 = -6 -6 + 3 * -1 = 3 You can do it easier by using a simple if/else: for (i = 0; i < 2500; i++) { if (i % 2 == 0) { System.out.println(3 * i); } else { System.out.println(-3 * i); } … Read more
Finally it works successfully ! public static int isMeera(int [] a){ boolean hasOdd = false; int firstEven = 0; int lastEven = 0; boolean firstCountEnd = false; boolean lastCountEnd = false; for(int i = 0; i<a.length; i++){ if (a[i]%2 == 1) { hasOdd = true; break; } } if (!hasOdd) return 0; for (int j … Read more
Remove .java in source code. change below line public class Bister.java { like this public class Bister { Your code will be like import java.util.Scanner; public class Bister { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.print(“Input first number: “); int num1 = in.nextInt(); System.out.print(“Input second number: “); int num2 = … Read more
You can use split to find all the matches String number = “128”; String digit = “2”; // expensive but simple. int matches = number.split(digit).length – 1; Say you want to use a loop and something like contains. // no objects char digit=”2″; int count = 0; for (int pos = number.indexOf(digit); pos >= 0; … Read more
Sample code is something like this: String str1 = “java;python;javascript;programming;Hello;World;Hello”; String str2 = “java;python;javascript;programming;Hello;World;Hello”; List<String> list = new ArrayList<String>(); list.addAll(Arrays.asList(str1.split(“;”))); list.addAll(Arrays.asList(str2.split(“;”))); for (String word : list) System.out.println(word + ” –> ” + Collections.frequency(list,word)); 1 solved Frequency distribution of words [duplicate]