Something like the following? if message.ReceiverId != self.loggedInUserUid { var newVariable = message.ReceiverId } else if message.senderId != self.loggedInUserUid { var newVariable = message.senderId } 0 solved swift if statement
The syntax of If Function in Excel is as follows: =IF(Logic_Test, Value_if_True, Value_if_False) your logic test: e10=”High” your value if true: 0.337 your value if false is the rest of your expression: if E10=Medium then return 0.086 or if E10=Low then return 0.017. Repeat the process: logic test: e10=”Medium” value if true: 0.086 value if … Read more
Just reindent your code you will find strange { like the one after printf(“Positive”); Juste removing this strange { and fixing your coding style will be: #include<stdio.h> int main() { int x; scanf(“%d”, &x); if ( x > 0 ) { printf(“Positive”); if ( x % 2 == 0 ) { printf(“Even”); } else { … Read more
You can use the ternary operator: string test = “It’s a test”; string test2 = (test != “”) ? test : “0-length string”; 5 solved C# Shorten if statement
There is no element “Savings found”. There may be an element that contains that string. Try if(apollo.Any(item => item.Contains(“Savings found”))) 3 solved Understanding if statement syntax in c#
You could defer the evaluation by collecting the values of the call. And then look with Array#some and Boolean as callback if some value is truthy. if ([checkPassword(), checkUserName()].some(Boolean)) { // … } 0 solved How to write an if statement in Javascript?
Where do You set color for the selected item? is it possible to set all colors to white and then use switch to set only the selected one to desired color? It would make it at least more pleasant to look at. nav_news_bg.setBackground(color); nav_feed_bg.setBackground(color); nav_profile_bg.setBackground(color); nav_chat_bg.setBackground(color); nav_books_bg.setBackground(color); switch(v.getId()){ case R.id.nav_news: nav_news_bg.setBackground(desiredColor); break; case R.id.nav_feed: . … Read more
You have two independent if statements. That the second such statement has an else suite doesn’t matter here; that else suite is picked on the basis of the condition attached to the second if test; whatever happened in the first if statement doesn’t matter. If you want the two x tests to not be independent, … Read more
if expressions have to be boolean. Say I have a string: string test = null; if (test) won’t compile because test is not a bool. It just returns the string reference. So, to check for null, you actually have to check for null: if (test != null) is an expression that does return a bool, … Read more
The first one is a nested if i.e. if(condition1) { if(condition2) { statement1 ; } statement2 ; } This will execute statemen1t only when both condition1 and condition2 are true and statement2 whenever condition1 is true. The execution is as follows: First condition1 is evaluated and checked. If it is true, the flow of control … Read more
They mistake was with the constructor function, it was just an typo. Because of which the head and tail pointers were not initializing and when the head pointer was compared against the nullptr in the if condition of the addToHead(), program was crashing. solved template program crashing during execution
Your first code fragment is badly indented, it should read: if (i1) if (i2) s1; else s2; Which is equivalent to your second fragment, but obviously very different from the third fragment: if (i1) { if (i2) s1; } else { s2; } This issue is called the dangling else problem. You can avoid it … Read more
Your vector has zero length at start vector<int> binV; //zero length In this line of code for (int i = 0; i < binV.size(); i++){//some code} Will not run because binV is empty This expression is not correct if (input == 1 && input == 0) //not valid This && is logical and operator, if … Read more
Indentation for the logical if-else block is misplaced.Also no input was taken for height variable. #include<stdio.h> int main(){ float a, pi = 3.14, r, c, d, h; printf(“Program to calculate area of circle and volume of cylinder \n”); printf(“select what you want to find?\n1.Area of circle\n2.Volume of cylinder\n”); scanf(“%f”, &c); if (c == 1) { … Read more
You better reconstruct it like: if ([startLocationAddress rangeOfString:@”Australia”].location == NSNotFound) { //codes.. } else { NSLog(@”startLocationAddress contain Australia”); } if ([endLocationAddress rangeOfString:@”Australia”].location == NSNotFound) { //codes.. } else { NSLog(@”endLocationAddress contain Australia”); } and review how if–else if–else statement works.. See: @ Hanky 웃 Panky answer for that, since confusion is very prone to us.. … Read more