[ad_1] Try something like this: foreach (DictionaryEntry i in hashtable) { if (i.Value is Ülke) { Ülke x = (Ülke)i.Value; Console.WriteLine(” ” + x.Ülke + ” ” + x.nüfus); } } 1 [ad_2] solved Convert object to integer in hashtable [closed]
[ad_1] Calculate the hash values of your number values in your set and count the number of duplicate hash values. A simple implementation of this may be: List<Integer> yourValues = /* Your set of numbers */; Map<Integer, Set<Integer>> map = new HashMap<>(); // Insert all elements into buckets based on their hash value yourValues.forEach(value -> … Read more
[ad_1] You can assume that I’m modifying a field of the object after I add the object to the HashMap. That right there is why. Javadoc says: Note: great care must be exercised if mutable objects are used as map keys. The behavior of a map is not specified if the value of an object … Read more
[ad_1] For synchronizing a HashMap,you can use Collections.synchronizedMap(<your hashmap reference>) which will return a synchronized map for you, which is thread-safe. [ad_2] solved How to change HashMap as Synchoronized
[ad_1] Q1: How to check if a value exists in hashmap? You need to iterate through and check if such item exists. You can use `std::find_if() with a lambda or do that through a loop. If you do that quite often you may want to index values as well (see below) Q2: How to iterate … Read more
[ad_1] Really? Hashtable MyHashTable = new Hashtable(); MyHashTable.Add(1, “word”); MyHashTable.Add(“word”, 12); // to access 12 int MyInt = (int)MyHashTable[“word”]; 3 [ad_2] solved how build a hash table stored object in C#?
[ad_1] Because for-loop needs 3 parameters. If you just give 2 parameters with 3rd parameter not being given, compiler expects the loop variant parameter there. Usually – for(iteration variable; condition; increment/decrement ) for(;condition;increment/decrement ){} for(iteration variable;;increment/decrement) {} for(;;increment/decrement) {} … 1 [ad_2] solved This just bugs me [closed]
[ad_1] Why not use a dict? collections.defaultdict would work too: d = defaultdict(list) for score, student in l: d[score] += student [ad_2] solved How to reorganize a list of tuples?