[ad_1] Your get Variable is wrong. You should also check if the get variable is set. <?php require ‘core.inc.php’; if (isset($_GET[‘id’]) { $id = $_GET[‘id’] if (isset($_POST[‘delete’])) { $answer = $_POST[‘decision’]; if ($answer == ‘yes’) { echo ‘user deleted’; } } echo ‘<h1>Are you sure you want to delete ‘.$id.’?</h1> <form name =”form1″ method =”POST” … Read more
[ad_1] Here is another way, without jQuery: <script> function update(){ let updateValue = document.getElementById(“name”).value; document.getElementById(“name2″).value = updateValue; } </script> <form action=”/new” method=”POST” > <input list=”name” type=”text” name=”name” id=”name” onchange=”update()”> <datalist id=”name”> <option value=”Hello”> <option value=”Hi”> </datalist> <button>Submit</button> </form> <form action=”/new1″ method=”POST”> <input type=”text” name=”name” id=”name2″ value=”name” > </form> 1 [ad_2] solved How to copy the … Read more
[ad_1] Without more information we are left to guess at what would help your situation. In order to process something like this, you’re most likely going to need a stronger, more processed language to work alongside HTML such as PHP, .NET, JavaScript or one of the many other choices. Your <form>‘s processing will need to … Read more
[ad_1] If I’m understanding, you are inserting new user information from Form 1 and then sending the user to a new page with a new form to fill out added information. Correct? … If so, simply retrieve the ID from the table where they were inserted and use that to insert data from Form 2. … Read more
[ad_1] I’ve used some of the suggestions in comments above, and changed around a few things myself and cleaned up the code. I’ve made it work… The primary changes were change the form method to post change your <button> to <input type=”submit”> please see this jsFiddle to see a working example of your code. Hope … Read more
[ad_1] It’s normal. When you do : $codering = [‘RF-013.12’]; Is same as : $codering = array(‘RF-013.12’); So if you try to use your array like string, php write array instead. If you wanna store [something] (a string with [] character) you need : $codering = “[something]”; If you realy need to store an array, … Read more
[ad_1] After submit run a loop and build your array. For example: var arr = []; $(form).find(‘input[name=”product”]’).each(function(index,element){ arr.push({ ‘label’: $(element).parent().find(‘label’).text(), ‘value’:$(element).val() }); }); [ad_2] solved Form ajax group label and value on submit
[ad_1] These links may help. Submit a form with Ajax and jQuery: http://net.tutsplus.com/tutorials/javascript-ajax/submit-a-form-without-page-refresh-using-jquery/ Validate a form: http://jqueryvalidation.org [ad_2] solved Submit a Form with Validations using AJAX and PHP [closed]
[ad_1] I can’t tell you what to do to make it “work”, since your desired result is pretty unclear, but a number of problems in your code jumped out at me as I skimmed it top to bottom. Some will still run but give results you aren’t expecting, but at least one problem will cause … Read more
[ad_1] You need inputs on your form: <form action=”insert.php” method=”post”> Username: <input type=”text” name=”username”> Password: <input type=”password” name=”password”> Confirm Password: <input type=”password” name=”confirm”> <input type=”submit” name=”submit”> </form> Then on insert.php if (isset($_POST[‘submit’])){ $Error = 0; if (!isset($_POST[‘username’])){ $Error++; } if (!isset($_POST[‘password’])){ $Error++; } if (!isset($_POST[‘confirm’])){ $Error++; } if ($Error > 0){ echo “Error in HTML … Read more
[ad_1] You can create an array with the references to the labels: Label[] labels = { eLabel1, eLabel2, eLabel3, … }; Producing an array with the texts from the labels would be a one-liner: string[] values = labels.Select(l => l.Text).ToArray(); [ad_2] solved c# faster way to read all textboxes/labels [closed]
[ad_1] Based on the paste in http://pastebin.com/0whCYxuE To fix your issue: Add the following as current line 30 echo ‘</form>’; And follow up suggestion is to remove line 28 and just utilize $_SESSION[‘user’] 2 [ad_2] solved Cannot POST all form fields [closed]
[ad_1] This is not black magic. The answer is by saving its data. You do this by putting it in a database, or writing data files. The trick is to write your programs in a way that makes it easy to guarantee that you’ve restored the state you thought you saved. A common approach is … Read more
[ad_1] It is default browser functionality ,you can change the setting using PHP only. You can use these syntax in your PHP config file before the session start: <?php session_cache_limiter (‘private, must-revalidate’); $cache_limiter = session_cache_limiter(); session_cache_expire(60); // in minutes ?> Now it will be not ask to re-submission the form. 0 [ad_2] solved Back to … Read more
[ad_1] Quick’n dirty solution : <?php $checked=isset($_POST[“radio”]) && $_POST[“radio”]===”oneway”?”checked”:””; ?> <input type=”radio” name=”radio” id=”oneway” value=”oneway” <?php echo $checked;?> /> but actually you should separate logic from template using a template engine like smarty or twig or mustache or whatever… 1 [ad_2] solved How to pass radio button value with php [closed]