I was able to edit a JavaScript file using regex. my code is below: function updateFile(filename, replacements) { return new Promise(function(resolve) { fs.readFile(filename, ‘utf-8’, function(err, data) { var regex, replaceStr; if (err) { throw (err); } else { regex = new RegExp(“(\\” + ‘let’ + “\\s* ]*” + replacements[0].rule + “\\s*=\\s*)([^\\n;}]+)([\\s*;}])”); replaceStr = “$1” + … Read more
First, you will have to write a function that will iterate the subjectDetails array and find the subject name based on a label. let subjectDetails = [{ “subjectLabels”: { “eng”: “english”, “sci”: “environment science”, “soc”: “History & Geo” } }] const getSubjectName = (label) => { let name = label; subjectDetails.forEach(details => { if(details.subjectLabels.hasOwnProperty(label)){ name … Read more
What you’re doing is called variable shadowing. When you declare a variable with const (or let) it’s block-scoped: the second time you’re declaring a new response constant you’re in a different scope, so they’re different variables. But the fact that they shares the same name, means you’re shadowing the outer one (that could potentially lead … Read more
You can use regex to split on capitals and then rejoin with space: .split(/(?=[A-Z])/).join(‘ ‘) let myStrings = [‘myString’,’myTestString’]; function myFormat(string){ return string.split(/(?=[A-Z])/).join(‘ ‘); } console.log(myFormat(myStrings[0])); console.log(myFormat(myStrings[1])); solved How can I write a function that will format a camel cased string to have spaces?
This is a good use case for reduce. const rawData = [ { date: ‘3/10/2019’, a: ‘123’, }, { date: ‘3/10/2019’, b: ‘456’, }, { date: ‘3/11/2019’, a: ‘789’, }, { date: ‘3/11/2019’, b: ‘012’, }, { date: ‘3/11/2019’, c: ‘345’, } ]; const groupByDate = array => array.reduce((results, item) => { const current = … Read more
It doesn’t return anything. You can check that by logging the result of the forEach call: var arr = [1, 3, 2]; var arr_temp = []; console.log(arr.forEach(function (i) { return arr_temp.push(i + i); })); // undefined console.log(arr_temp); // 2, 6, 4 3 solved .forEach() Javascript function is returning an Array?
Essentially, the code you provided is looping through each element in votes and checking whether it is greater than an element stored at a particular index. This index is stored in the variable bestIndex an is used to mark/keep track of the index which holds the largest element from all elements seen while looping. In … Read more
Assuming that values is actually an object, check if .some of the Object.values of the object are true: const values = {de: true, en: false, nl: false, pl: false, ru: false}; const someTruthy = Object.values(values).some(val => val === true); console.log(someTruthy); (if the only truthy value is true, you can use (val => val) instead) solved … Read more
I try to use syntactic sugar The conditional operator is not syntactic sugar. It’s a specific operator with a specific purpose, and you’re simply using it incorrectly. It is used for conditionally producing a value as an overall expression, one value if the condition is true and another if it’s false. For example: let x … Read more
const bidder= [ [1,2,3,4], [5,6,7,8] ] const arr1 = [9,10,11,12]; const result = […bidder, arr1]; console.log(result); You can use spread operator to spread whatever is in bidder array and add your other array as the last one in a new array. solved How to concatenate this array [duplicate]
It’s part of the ES6 module system, described here. There is a helpful example in that documentation, also: If a module defines a default export: // foo.js export default function() { console.log(“hello!”) } then you can import that default export by omitting the curly braces: import foo from “foo”; foo(); // hello! Update: As of … Read more
You can use .reduce() and Object.entries() methods: const aa = [‘red’, ‘yellow’, ‘blue’] const bb = { first: 0, second: 1, third: 2 } const cc = Object.entries(bb) .reduce((r, [k, i]) => (r[k] = aa[i], r), {}); console.log(cc); solved JavaScript – array, object – How can I streamline this code
You can do it using Array#map() to create a new array and Array#find() to find the object in the second array let arr=[{status:”ok”},{status:”ok”},{status:”error”}], arr2=[{status:”error”,msg:”etc”,”more property”:!0}]; arr = arr.map(a=>{ let fullObj = arr2.find(a2=>a2.status===a.status); return fullObj ? fullObj : a; }); console.log(arr); 3 solved replace array of object with another array of object base on property
The yield and yield* keywords can only be used directly inside a generator function. Your code fragment is conceptually flawed in a similar manner to: function f1() { if(someCondition) { f2((value) => { else { // do something } }); } } or, to this: function f1() { f2((value) => { return someValue; // while … Read more
You can just access Object.values() data.item3 = Object.values(data.item3) 1 solved convert an Object to an Array in javascript