Yes, the output is correct: // This line increments the variable then prints its value. Console.WriteLine(“{0}”, ++ Cash); // This prints the value of the (incremented variable) Console.WriteLine(“{0}”, Cash); // The prints the value of the variable *then* increments its value Console.WriteLine(“{0}”, Cash ++); 1 solved C# help declaring variable i initialize it to
The order in which the arguments passed to a function are evaluated is not specified, and the order of evaluating the operants of + is unspecified, too. So in printf(“%d %d”, i+1, i-1), for example, you cannot rely on the order of evaluation of the arguments; i+1 might be evaluated after i-1, actually; You will … Read more
You need to understand the concepts of post increment(decrement) and pre increment(decrement). Post increment cout << x++<<endl; You can understand this line as “Return the value of x” + “increment the value of x”. I.e The return value is before the increment. So return 0 and increase the value of x to 1. Pre increment … Read more
A correct program can look for example the following way #include <iostream> int main() { int num, a = 15; num = ( —-a )–; std::cout << num << std::endl; std::cout << a << std::endl; return 0; } Its output is 13 12 The post-decrement operator has a higher priority than the pre-decrement operator and … Read more
if c=12 then c++ + ++c is 12 + 14 = 26, so 26 will be assigned to c. First the c++ is evaluated to 12 and then 13 is assigned to c. Then ++c first assigns 13+1 is 14 to c and results in 14. So we have 12 + 14 which is the … Read more