Introduction This question is related to the comparison of const char* if() with “SRAD” and whether it returns false. The const char* if() comparison is a type of comparison used in C++ programming language. It is used to compare two strings and determine if they are equal or not. In this case, the comparison is … Read more
This compares the pointers, not the contents. You need to use strcmp: if(strcmp(“SRAD”, name) == 0) 1 solved const char* if() comparison with “SRAD” returns false [duplicate]
To know how all these three code blocks works, you got to start reading good C book specially array and pointers concept. Case 1 :- In the below code block int main(void) { char x[] = “gate2011”; char *ptr = x; printf (“%s”, ptr+ptr[3]-ptr[1]); return 0; } It looks like x[0] x[1] x[2] x[3] x[4] … Read more
Just add at the bottom of your code std::cout << name1 << ” ” <<name2 << std::endl; and you will see wonders. don’t forget to do delete[] name1; solved what happens when I run char * name1 = new char[ 6 ]; strcpy( name1, “Henry” ); char * name2 = name1; name1[0] = ‘D’;
You could check for ‘Hi’ at index 0. var text = “Hi I am Anonymous”; if (text.indexOf(“Hi”) === 0) { document.getElementById(“test”).innerHTML = “Hey Anonymous”; } <p id=”test”></p> 0 solved Check for the value Of a var and reply If it includes the character “Hi” [closed]
You can use the strncmp function to compare two strings up to a maximum number of characters. To start a comparison in the middle of a string, you would pass in the address of the array element to start the comparison at. For example: if (strncmp(&string1[4], &string2[4], 4) == 0) { printf(“characters 5 – 8 … Read more
You need A separate index for writing to szBuffer Code that adds a zero termination to szBuffer Like: int j = 0; // Index for storing in szBuffer for (int i = 0; i < StrLenght – 1; i++) { if (szPattern[i] == ‘%’) { // DO stuff…. } else { szBuffer[j] = szPattern[i]; // … Read more
To pass literal string to a function, it must have a parameter of type char const *, not char *. So your constructor should have this prototype: Etudiant(char const * c, unsigned int, Date &); Saying the above, you also do not allocate enough memory to copy a string in your constructor. This line: this->name … Read more
“blah” is a const char [5]. In the first line, that array is decayed into a pointer to be stored in your variable as a pointer to the first element. It is also a pointer to non-const characters that points to const characters. It should be: const char *sz1 = “blah”; In the second (thanks … Read more
what is the reason behind this output? The values in an automatic variable are indeterminate. The standard doesn’t specify it, so it might be spaces as you said, it might be random content. […] sometimes not fully filled and I left with junk […] Strings in C are null-terminated, so any routine dedicated to printing … Read more
Error was in v_push_back implementation : v->e_array = check_a(memcpy((void*)((char*)v->e_array + (v->no_e * v->e_sz)) ,new_val, v->e_sz)); //pointer has not to be saved check_a(memcpy((void*)((char*)v->e_array + (v->no_e * v->e_sz)) ,new_val, v->e_sz)); Because memcpy returns a pointer , in this case, to the last element of the array so we would have lost access to all previous memory solved … Read more
Yes, that’s true. If you insist on having a char* parameter, call CreateProcessA instead of CreateProcess. Otherwise, make path an LPWSTR too and bring your program into this millenium. solved char* incompatible with parameter of LPWSTR for C++ [duplicate]
I think you are looking for this: #include<cstdlib> int v; for(int i=0; i<10; i++) { v = rand() %6; printf(“%s\n”, words[v]); } 1 solved Outputting to console from Char Array
try this, String s = “25999993654”; System.out.println(Character.getNumericValue(s.charAt(0)) + Character.getNumericValue(s.charAt(1))); 1 solved Can I product of charAt in Java? [duplicate]
Not sure if this is the best way, performance wise, but it is the most logical way to me. copy_if seem to not exist. But looking at ASCII table www.asciitable.com I loop through the character array and only copy the alphabetic numeric character to my string object, and until I find a space or reach … Read more