[Solved] while trying to print the address of a[1] error: lvalue required as unary ‘&’ operand pops up

Question

For any array or pointer a and index i, the expression a[i] is exactly equal to *(a + i). From that we can draw the conclusion that a + i is a pointer which is equal to &a[i].

So when you try to do &(a + 1) that’s really equal to &&a[1] which makes no sense and gives you an error.

Accepted Answer

For any array or pointer a and index i, the expression a[i] is exactly equal to *(a + i). From that we can draw the conclusion that a + i is a pointer which is equal to &a[i].

So when you try to do &(a + 1) that’s really equal to &&a[1] which makes no sense and gives you an error.