[Solved] Evaluating C binary operations
k=25; ++k; k++; k|7&12; After the first 3 lines, k is 27. In the fourth expression, the bitwise AND operator & has higher precedence than the bitwise OR operator |, so it is equivalent to 27|(7&12); Converting the values to binary gives us 11011|(00111&01100); The inner part evaluates to 00100, then 11011|00100 evaluates to 11111, … Read more