This can be done by overwriting the Control Template. Here is a very rough example to get you started. EDIT Updated Path to be L shape <Button > <Button.Template> <ControlTemplate> <Border> <Grid> <Polygon Points=”300,200 200,200 200,300 250,300 250,250 300,250″ Fill=”Purple” /> </Grid> </Border> </ControlTemplate> </Button.Template> </Button> 1 solved WPF How can i make a button … Read more
Not sure I get your question right but my bet is you’re asking how to convert between ASCII and number representation of characters. Encoding/Decoding has nothing to do with RSA. You just use dynamic range shift. As the alphabet is in increasing order in ASCII so the only thing left is to offset the a … Read more
I’m not sure if this is what you need(it’s a random shot since your question is not complete): Dim orderedData = From d In collezione Order By d.Gruppo Group d By d.Gruppo Into g = Group From d In g Select New With { .withChildren = {d}. Union(g.Where(Function(c) c.Owner = d.Comp)) } Dim result = … Read more
How to send e-mail programmatically by using System.Web.Mail in Visual C# 2005 or in Visual C# .NET (this is still applicable, paste the code into Page_Load) solved Send email from ASP.NET page [closed]
I don’t really understand the purpose of what you are asking but this works #include “omp.h” #include <iostream> using namespace std; int main() { #pragma omp parallel { int nthreads = omp_get_num_threads(); for(int i=nthreads-1; i>=0; i–) { #pragma omp barrier { if(i==omp_get_thread_num()) { #pragma omp critical cout << “I am thread “<< i <<endl; } … Read more
You want all permutations of each member of the powerset of the input. permSub(“abc”, “”) func permSub(input, perm) print perm if input = “” return for i = 0 to input.length-1 permSub(input[0..i]+input[i+1..input.length), perm+input[i] end end Where input[i..j] represents the sub string of input from i(inclusive) to j(exclusive), and + is string concatenation. Note that this … Read more
Are you sure that it isn’t starting at i = 2 and j = 2? You are running this loop so many times that your console output may not show that it starts at 2,2, even though it does. Try setting a breakpoint in the second for loop, I think you’ll see it is starting … Read more
You practically already answered your question: Because declaration does not assign a value. Therefore your second sample never makes sense. The first sample consists of two separate statements each of which could make sense in a certain context. Therefore it compiles. 1 solved Why can’t variables be declared and modified at once? (C++)
OK, so, your database actually only needs one user (possibly also known as a schema, depending on your database), unless you want to limit who can do what. Then, you need to configure your database to allow remote connections. Once that’s done, you’ll be able to get something called a “connection string”, which can be … Read more
Does this mean that x holds the address of first element of the string,i.e, the character ‘g’ ? Yes. is it the placeholder %s that’s instructing the printf to print the string literals ? Yes. To be more specific, %s is not limited for string literals. It is for printing null terminated srings – which … Read more
with the values 3 5 3 1 the test if(xp1!=xp2 && yp1!=yp2){ is false because xp1 and xp2 value 5, so you do nothing And as I said in a remark if(x1<=1000000 && x1>0 && x2<=1000000 && x2>0 && y1<=1000000 && y1>0 && y1<=1000000 && y1>0){ must be if(x1<=1000000 && x1>0 && x2<=1000000 && x2>0 … Read more
The outer vector must first be explicitly grown, before one can push to its elements. This may be a little surprising since STL map’s automatically insert their keys. But, it’s certainly the way it is. #include <iostream> #include <vector> #include <string> using namespace std; int main() { const int DESIRED_VECTOR_SIZE = 1; std::string * foo … Read more
This does not work well with the standard incoming webhook, since you will need to create a webhook for each user (as you stated). Alternatively you can use the legacy version of the incoming webhook, which allows you to override the channel and which you can install from the app store. However, this is not … Read more
How about this: if (oldLines.Count() == newLines.Count()) { lbOne.Items.Add(txtID.Text + ” does not exist.”); } else { lbOne.Items.Add(txtID.Text + ” was deleted.”); } 4 solved How can I get a message if a string does not exist?
string json = “{Table1: [{\”PropertyTaxReceiptAmt\”:\”2200170.00\”,\”WaterTaxReceiptAmt\”:\”79265.00\”}]}”; json = json.Replace(“\\”, string.Empty); json = json.Trim(‘”‘); json = json.Replace(“{Table1:”, string.Empty); json = json.Remove(json.Length -1,1); Console.Write(json); 1 solved Remove character from json string