[ad_1] You’ll need a little loop: public bool Yahtzee() { // check if all dobbelstenen[int] are the same for(int i = 1; i < 5; i++) // start with second dobbelstenen { if(dobbelstenen[i] != dobbelstenen[0]) return false; } return true; } It simply compares second, third, … against the first. 1 [ad_2] solved c# best … Read more
[ad_1] public Int64 id(string fd, string tb) { Int64 I = 0; if (con.State == ConnectionState.Open) { con.Close(); else { con.Open(); } SqlCommand cmd = new SqlCommand(“SELECT MAX (” + fd + “) FROM ” + tb + “”, con); cmd.CommandType = CommandType.Text; if (con.State == ConnectionState.Closed) { con.Open(); I = Convert.ToInt64((cmd.ExecuteScalar().Equals(DBNull.Value) ? 0 : … Read more
[ad_1] “I don’t underastand what Class1() :a(3) means.” It’s called member initializer list, and initializes the class member variable a with the value 3. Also see What is this weird colon-member (“ : ”) syntax in the constructor? [ad_2] solved Operator overload () [duplicate]
[ad_1] You should store the invitation KEY against your each unique email ID list. So when user register using your KEY you can either remove that email form Pending Invitation List or alternatively use flag bit to mark as registered. [ad_2] solved Invitation using a token [closed]
[ad_1] What you want to accomplish is called de-serialisation or de-marshalling. For values that wide, using a loop is a good idea, unless you really need the max. speed and your compiler does not vectorise loops: uint8_t array[6]; … uint64_t value = 0; uint8_t *p = array; for ( int i = (sizeof(array) – 1) … Read more
[ad_1] You can’t iterate through a list with an integer, but you can declare j as an iterator (std::list<int>::iterator j = adjList[i].begin();) and use the asterisk like in pointers to get the element that an iterator is pointing at like this: cout << *j << ‘ ‘;. If you want to print a vector of … Read more
[ad_1] You may not change a string literal that way. https://stackoverflow.com/a/17507772/234307 “A C string literal creates an anonymous array of char. Any attempt to modify that array has undefined behavior.” – Keith Thompson 1 [ad_2] solved Unable to alter a character in string literal Via pointer [duplicate]
[ad_1] This one should works double sum(double n) { double formula = 0; for(int i=1; i<=n; i++) formula += double(i)/double((i+1)); return formula; } 9 [ad_2] solved Calculating sum formula in c++ [closed]
[ad_1] Answer was provided before language tag was changed from C to C++. struct MyStructData { VOID* pPtr; UINT32 flags; } There are no types VOID or UINT32 in C unless you include some headers providing them. Maybe some Windows stuff? Also a ; is missing after that struct declaration. (Thanks to wildplasser) VOID main() … Read more
[ad_1] C standard says: C11: 6.5 (p2): If a side effect on a scalar object is unsequenced relative to either a different side effect on the same scalar object or a value computation using the value of the same scalar object, the behavior is undefined […] This means your program invokes undefined behavior. In the … Read more
[ad_1] You can write a state machine that should handle most cases. As you scan the file, you’ll be in one of the following states: TEXT – regular (non-commented) text; this is the state you’ll start in. Any newline seen in this state will cause the total-lines counter to be incremented. SAW_SLASH – You’ve seen … Read more
[ad_1] int main() { int i,j; // declaration of i and j int *x; // x points to an integer i = 1; // initialization of i = 1 x = &i; // initialization of x = address of i j = *x; // initialization of j = value of what pointed by x => … Read more
[ad_1] You’re close. You already figured out your bounds problem, but consider what happens at the interface of clusters: ..2,2,3,3… ^ ^ i i+1 You are going to enter the else (else if is unnecessary if the condition is the exact opposite of the original if) and forget to add that last 2. If there … Read more
[ad_1] To answer your specific question: You are not printing anything. Add this to your code for (vector<Car*>::const_iterator iter = cars.begin(); iter != cars.end(); ++iter) (*iter)->print(); [ad_2] solved Implement a class Person with two fields name and age, and a class Car with three fields [closed]
[ad_1] It’s hard to say for sure what you’re asking. I think you’re asking how the system knows that it should execute the iconType_CheckChanged method when one of the icon radio buttons is clicked, and how it knows that, for example, the asteriskRadioButton changed. The answer is in two parts. First, in creating the program … Read more