[ad_1] set { TimeZone = value; } The setter is recursive. You must use a field like: string _timeZone; public string TimeZone { get { if (_timeZone== null) return “”; return _timeZone; } set { _timeZone= value; } } 1 [ad_2] solved Why would this simple code cause a stack overflow exception?
[ad_1] This should be enough to get you started: var files = Directory.GetFiles(path); foreach (var f in files) { var info = new FileInfo(f); var name = info.Name.Split(‘.’)[0]; var extension = info.Name.Split(‘.’)[1]; int i; if (int.TryParse(name, out i)) { File.Move(info.FullName, string.Format(@”{0}\{1}.{2}”, path, i + 5, extension)); } } 2 [ad_2] solved Is it possible in … Read more
[ad_1] It seems I was getting this Not Responding on my program, because the other thread I had, that was running constantly, didn’t had any Sleep in it, and was running as fast as possible, thus making the program Not Responding and using up to 13% of the CPU… A simple Thread.Sleep(10); fixed everything [ad_2] … Read more
[ad_1] One way to track down the problem without stepping through the debugger is to write values of the key data in important lines. Also, since you know that you have an infinite loop, add code to limit the number of times the loop gets executed. #include <iostream> #include <vector> #include <algorithm> using namespace std; … Read more
[ad_1] The .h usually has the class definition (code) #ifndef CLASS_T_H #define CLASS_T_H class class_t { public: class_t(); class_t(const class_t& o); ~class_t(); class_t& operator=(const class_t& o); private: }; #endif And the .cpp usually has the class implementation (code) #include “class_t.h” class_t::class_t() { } class_t::class_t(const class_t& o) { } class_t::~class_t() { } class_t& class_t::operator=(const class_t& o) … Read more
[ad_1] Integers don’t have fractions. Use decimal if you want reliable numeric values with decimals. decimal box1 = decimal.Parse(Number1TextBox.Text); decimal box2 = decimal.Parse(Number2TextBox.Text); decimal box3 = decimal.Parse(Number3TextBox.Text); decimal answer = box1 * box2 * box3; You can round back the result like this: decimal rounded = Math.Round(answer); 5 [ad_2] solved C# basic Math, want to … Read more
[ad_1] Your code invoke UB. tree_node *root; … c=b.search(root,number); // root is uninitialized To solve this add a new function: class bst { … int search(tree_node * ,int); int search(int v) { return search(root, v); } }; Also in bst::search function: else //if (root != NULL){ Comment this condition if(root->data == data) { // r=”t”; … Read more
[ad_1] for(int i = 0; ; i++) When does your loop end?!?!? Your second condition in for (the testing expression) is evaluated as true (at least as long as i<4). You need for(int i = 0; i < 4 ; i++) Otherwise it may break anytime after i>=4, but not before, since all components of … Read more
[ad_1] Designate a register to be a counter (pick any one you aren’t using for other stuff) and set its value to 0. When you hit a * character, push characters onto the stack until it finds a blank, incrementing the counter with each push. When a blank is found, pop characters off the stack, … Read more
[ad_1] You will need to escape the quotation mark you require in the string; std::string str(“Q850?51’18.23\””); // ^ escape the quote here The cppreference site has a list of these escape sequences. Alternatively you are use a raw string literal; std::string str = R”(Q850?51’18.23″)”; The second part of the problem is dependent on the format … Read more
[ad_1] Yes, signed integer overflow has undefined behavior in C. i > INT_MAX is never true for any int i. How can you have an int greater than the maximum possible int? [ad_2] solved Strange behaviour when intentionally assigning `i` value greater than INT_MAX [duplicate]
[ad_1] You can use break. It breaks the loop you are in right now. Plus, in your condition you should use else if rather than multiple if. foreach (var pair in firstStrings) { foreach (var pair2 in secondStrings) { if (secondStrings.ContainsKey(pair.Key)) { LogMessage( pair.Value + ” <———-> ” + pair2.Value + ” On Line ” … Read more
[ad_1] *(num+1)[1] and **(num+2) are different ways of writing the same thing. That is, the third element of num. The type of num is short (*)[2]. That is, it is a pointer to an array of 2 short values. With these two facts in mind we can work out what the code is doing. Below … Read more
[ad_1] You need to put your code within the for block. Remove the semicolon For(i=1;i<=num;i++) { // code here } 2 [ad_2] solved I am thinking about for loop termination is it halts the loop or what’s the actual story [closed]
[ad_1] You need to tell the SMTP client that you will not be using your windows credentials to access the SMTP, so add smtpClient.UseDefaultCredentials = false; above this line of code smtpClient.Credentials = new NetworkCredential(“[email protected]”, “password”); Also, gmail doesn’t allow impersonation, so mailMessage.From = new MailAddress(“[email protected]”); will have no effect – the emails will still … Read more