[ad_1] string snack2[][]=new string[Math.Round(snacks.Length/2)][2]; int cnt=0; for(int i=0;i<Math.Round(snacks.Length/2);i++) { for (int j=0;j<2;j++) { snacks2[i][j]=snack[cnt++]; } } 3 [ad_2] solved How To convert 1D array to 2D array in C# [closed]
[ad_1] In the remove function, you must update tailif the list becomes empty. int removeFirst() { List *nodeToRemove; int dataToRemove; if (head->next == NULL) { prtError(“Empty list!”); return -1; } else { nodeToRemove = head->next; dataToRemove = nodeToRemove->data; head->next = nodeToRemove->next; free(nodeToRemove); // Update tail if list is empty if (head->next == NULL) { tail … Read more
[ad_1] You can try this, by simply using char as binary operator and the Increment and Decrement can be applied on chars as well as on integer. If you want to get input from the user you can use the scanf(“%c”) to read the chars and use them char i,j; for ( i = ‘G’; … Read more
[ad_1] Change your method to private string NumbersToWords(int number) { string word = “”; if (number == 8) { word = “Eight”; } return word; } Previously you did not return a value, indicated by void. 3 [ad_2] solved C# convert a number into words
[ad_1] You can just read it in as a string. int main() { char str[80]; fgets(str, 80, stdin); strrev(str); printf(“%s\n”, str); } void strrev(char *str) { char *end, tmp; end = str + strlen(str) – 1; for (; end > str; –end, ++str) { tmp = *end; *end = *str; *str = tmp; } } … Read more
[ad_1] Unsigned char’s (assuming char is only eight bits) can only represent 28 numbers, from 0 to 255. You’ll need to use another type such as int to represent this. 2 [ad_2] solved Exceeding unsigned boundary [closed]
[ad_1] I was wondering if there is a better way of achieving this in C# without iterating through each directory and storing the details in a separate list. Use EnumerateFiles on both directories, zip-join them, and then run the join through a foreach loop. var firstFiles = Directory.EnumerateFiles(…); var secondFiles = Directory.EnumerateFiles(…); var joined = … Read more
[ad_1] Seats will be null if you call the method without matching data / query argument. You need to also check that, like so for instance: [HttpPost] public String Indexhome( IEnumerable<Seat> Seats ) { if ((Seats == null) || !Seats.Any(s => s.IsSelected)) { return “you didnt select any seats”; } else { return “you selected … Read more
[ad_1] You cannot use a dictionary of Booleans, because it is limited to only two values. This will inevitably lead to key collisions, because you plan to add more than two items to it. Good news is that you do not need a dictionary anyway, because you use it as a collection of tuples. This … Read more
[ad_1] On line 161 you are doing an else if but there fore you did’nt specify any if. I don’t know what your doing in your code. But either remove the else in the else if statement or create an if statement before the else if. An else if statement comes after an if statement … Read more
[ad_1] You cannot convert a string literal to a shared pointer. Let me just “correct” your code, and then all you have remaining is undefined behavior: const char *str = “abcdfg”; boost::shared_ptr<char> ss(str); Now, this will compile, but it will produce serious problems because str is not memory that was allocated dynamically. As soon as … Read more
[ad_1] This operator+ is used here (a pointer to single char that is not null-terminated is not really suitable). Yes, most definitely undefined behavior. lhs – string, character, or pointer to the first character in a null-terminated array Just make std::string the common type to fix it: ((d == ‘\0’) ? std::string(“null character”) : std::string(1, … Read more
[ad_1] Because comp1(a,b) and comp1(b,a) can both return true, which isn’t allowed. std::sort states that: comp – comparison function object (i.e. an object that satisfies the requirements of Compare) which returns ​true if the first argument is less than (i.e. is ordered before) the second. And following the link to Compare we also see: Establishes … Read more
[ad_1] Although the question might not be too precise, I think I still got the point: Imagine, the code would have been written as follows: Widget& Widget::operator=(const Widget& rhs) { if (rhs == *this) // actually, you’d rather do &rhs == this! // you don’t want self-assignment return; delete pb; pb = new Bitmap(*rhs.pb); return … Read more
[ad_1] You just need to pass parameters no need specify parameter type when calling the function in c. Change h=add(int x, int y); to h=add(x,y); have a look at this:-http://www.techcrashcourse.com/2015/05/c-programming-function-calling.html [ad_2] solved given two integers write a program that uses function add() to add these numbers and sub() to find the difference [closed]