22, in binary 0000000000010110 225, in binary 0000000011100001 222, in binary 0000000011011110 | is binary OR operator: The binary OR operation has two inputs and one output. It is like the ADD operation which takes two arguments (two inputs) and produces one result (one output). A B C 0 OR 0 -> 0 0 OR … Read more
Both will give the same result, but I’d choose the | always, because you are dealing with bits, not numbers. In order to understand why they are equivalent you first have to understand binary numbers and binary maths: var b = 0b0011; //binary 0011 Ok, lets do something similar to your code: var s = … Read more
Without context, it’s just hard to understand your question. The last 3 bytes of the hash “742da831d2b657fa53d347301ec610e1ebf8a3d0” you give are “f8a3d0”, which are the last 6 characters “F8A3D0” in “SpeedTouchF8A3D0”. The first 5 bytes of the hash “742da831d2b657fa53d347301ec610e1ebf8a3d0” are “742da831d2”, which gives the 10-character string you are referring to: “742DA831D2”. 1 solved How many bytes … Read more
Declare a string value and append to it on each iteration, then set the textbox.text property value. using System; using System.Collections.Generic; using System.Drawing; using System.Windows.Forms; using System.IO; namespace encrypto { public partial class MainForm : Form { public MainForm() { InitializeComponent(); } void OnClick(object sender, EventArgs e) { string Plaintext = textBox1.Text; string byteText = … Read more
In-place? Probably something like this: byte[] Reverse( byte[] b ) { for ( int i = 0 , int j = b.Length-1 ; i < j ; ++i, –j ) { arr[i] ^= arr[j] ; arr[j] ^= arr[i] ; arr[i] ^= arr[j] ; } return b; } Idempotent, where you allocate a new array to … Read more
Existing Delphi code translation: public static string ByteToHex(Byte InByte) { char[] Digits = new char[] { ‘0’, ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, ‘6’, ‘7’, ‘8’, ‘9’, ‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, }; return string.Concat(Digits[InByte >> 4], Digits[InByte & 0x0F]); } Better implementation (all you want is formatting): public static string ByteToHex(Byte InByte) => InByte.ToString(“X2”); … Read more
I want to understand the working of this Java program in detail? Why are we doing it and how are we taking such values to solve this? solved I want to understand the working of this Java program in detail? Why are we doing it and how are we taking such values to solve this?
I think you’re looking to iterate over the byte array and find the absolute value of each element. Math.abs() should work for that. https://www.geeksforgeeks.org/java-math-abs-method-examples/ solved Setting all values in a byte array positiv [closed]
You might want to read Read ints from file in python It is even more straightforward from that question. I have not checked the following code but something along the spirit of fin = open(“hi.bmp”, “rb”) out = open(“values.txt”,”rw”) value = struct.unpack(‘i’, fin.read(4))[0] out.write(“%d\n” % value) # just loop over the 2 last lines out.close() … Read more
In C and C++, regular character strings are terminated by a ‘\0’ character. So it appears you are using a string function to copy the data. That is, it stops copying once it hits the ‘\0’ value. Interestingly, you left the part that copies the data (and maybe just the part the displays the data) … Read more
Buff_Y[2] = (Y / 100) + 0x30; Buff_Y[1] = (Y / 10) % 10+0x30; Buff_Y[0] = (Y % 10) + 0x30; This is all good. If you print those three bytes, you will see that they contain the right values. SBUF = *Buff_Y; This, however, indicates confusion. *Buff_Y is equivalent to Buff_Y[0]. That is a … Read more
Bytes don’t have an encoding. They’re bytes. See the Javadoc of String.getBytes(): Encodes this String into a sequence of bytes using the platform’s default charset So, it’s whatever your default charset is. You can find out what that is at runtime using Charset.defaultCharset(). If you want the bytes in a particular charset, specify it, e.g.: … Read more
Dim bArr As Byte() = New Byte(1) {&H1B, &H68} You can use http://converter.telerik.com/ in future. 1 solved Add to byte array in VB.net
Here’s an example using multipart request. I modified this from a piece of code I have that deals with JSON docs, so there may be some mistakes in it, but it should give you the idea: body := bytes.Buffer{} writer := multipart.NewWriter(&body) hdr := textproto.MIMEHeader{} hdr.Set(“Content-Type”, “text/plain”) part, _ := writer.CreatePart(hdr) part.Write(data1) hdr = textproto.MIMEHeader{} … Read more
One solution in your case (unless you have strict restriction on space usage) would be to copy your file into another skipping bytes that you do not need. Depends on how you count nth byte you may need to open files in binary mode. You may rename source file to temp open new file with … Read more