plain bash, though can easily be converted to POSIX sh. #!/usr/bin/env bash in=0 # whether we are inside a ‘virtual’ block # such a block ends once we meet a line that starts with ‘}’ while read -r do if [[ $REPLY =~ ^virtual ]]; then in=1 echo “${REPLY% *}” elif (( in )); then … Read more
This Bash script will: Set the source directory (SOURCE). Set the destination backup directory (BACKUP). Set the destination directory for latest full backup (LBACKUP). Get the current system date in Y-m-d-Time format (DATE). Sets the destination directory as BACKUP+/+DATE+-diff. Rsync/copy the files from the SOURCE to the DESTINATION folder by comparing the files from LBACKUP … Read more
Consider adding a counter, bump it up on every line, and print the counter with every line. Also note fixes to set log_file, update to read command. log_file=”/home/user/log.txt” line_no=0 while read -r line do line_no=$((line_no+1)) printf “%d. %s\n” $line_no “$line” done < “$log_file” One alternative to consider is to call the nl utility, which performs … Read more
You can use this. if [ “$1” != “something1” ] && [ “$1” != “something2” ] && [ “$1” != “something2” ]; then echo “Result is $1” # do stuff here if $1 is not equals to one of the above “somethings” fi Reason is even though one OR condition fails in your example, other … Read more
Your perl backreferences are incorrect: perl -lne ‘$a{$1}++ if (/^(Unexpected exception) : (.*?)\s*$/) ^^^^^^^^^^^^^^^^^^^^^-$1 ^^^^^-$2 You want $a{$2}++ instead. Or convert that first () to a non-capturing group: (?:Un….) 1 solved A perl script to list all the exceptions and their number of occurrence
Your script has a number of problems. Here is the minimal list of fixes to get it working: While is not a bash control statement, it’s while. Case is important. Whitespace is important: if [“$CHECKMOUNT”= “true”] doesn’t work and should cause error messages. You need spaces around the brackets and around the =, like so: … Read more
If you want to do it in pure bash, use the following script: #!/bin/bash while read line; do line=( ${line//[:]/ } ) for i in “${!line[@]}”; do [ ! -z “${line[$i]##*[!0-9]*}” ] && printf “integer” || printf “string” [ “$i” -ne $(( ${#line[@]} – 1)) ] && printf “:” || echo done done < $1 … Read more
Use this: grep -A 1 -B 1 ‘Server sent’ file.txt | sed ‘/^–$/d’ (OR) grep -C 1 ‘Server sent’ file.txt | sed ‘/^–$/d’ 0 solved Print every 3 strings who are start from special symbols
env sets one or more environment variables and then runs the remaining arguments as a command. It’s not significantly different from the following syntax: x='() { :;}; echo vulnerable’ bash -c “echo this is a test” One thing env can do (although the feature is not used in the above example) is create a clean … Read more
I think you are asking to have the script feed a specific number to the executable’s standard input. This is done as follows: echo $number | ./exec 1 solved How can I write a number into a executable from a script [closed]
You could simply do this through awk, $ awk -F[,-] ‘{var=$1″-“$2; for (i=3;i<=NF;i++){print var”-“$i}}’ file 86-22-63385835 86-22-63385836 86-22-63385933 86-0577-88609993 86-0577-88835386 86-21-58947602 86-21-58947603 0086-755-33186858 0086-755-33186862 0086-755-33186859 2 solved How to process this text [closed]
The following awk script should solve your probelm provided you manually add the School heading yourself or if that remains same add it as BEGIN { printf “School” } in below example. $ cat input_file Mark,Texas High, Dallas, k-5 Steve,SA high,Antonio,k-5 Adam,Plano tech,k-5 $ awk -F, ‘BEGIN { sep = “”} { printf(“%s%s”, sep, $2); … Read more
grep -oP ‘^server\s\K[^ ]+|^[^#]\s+\d+:\K[^:]+’ inputfile pool0 server1 server2 pool1 server3 server4 4 solved Extract specific string between two strings and list the required content
You can do it like this with bash and ImageMagick: #!/bin/bash convert -crop 16×16@ input.jpg tile.jpg montage -geometry +0+0 $(ls tile*jpg | awk ‘BEGIN{srand()}{print rand() “\t” $0}’ | sort -n | cut -f2-) output.png # Remember to remove the tile*jpg before you do another one 🙂 # rm tile*jpg Basically as you suggest, using -crop … Read more
Because your awk program is in single quotes, there will not be any shell variable expansion. In this example: awk ‘tolower($0)~/^alphabet/{print}’ titles-sorted.txt > titles-links/^alphabet.txt …you are looking for the lines that begin with the literal string alphabet. This would work: awk “tolower(\$0)~/^$alphabet/{print}” titles-sorted.txt > titles-links/$alphabet.txt Note several points: We are using double quotes, which does … Read more