You don’t show much effort to let us help you solving this. But since I’m learning bash scripting, I took your question as practicing. So… here is a bash script to rename duplicated files. /!\ The renamed files will be in the folder of first argument. So, in your case, you’ll have to launch it … Read more
From what we can discern of this question, you’re attempting to create a programmatic rule to rename files ending in extensions stdout-captured, stderr-captured, and status-captured (assuming one typo) into files ending in extensions stdout-expected, stderr-expected, and status-expected, respectively. Obviously, if each of these definitions is inclusive of exactly one file, a rote mv may be … Read more
cat file1 1 10.0 2 12.1 3 5.2 4 13.0 cat file2 15 11.1 10 12.3 17 2.1 12 15.5 11 7.0 command : awk -f script.awk file2 file1 script.awk #! /bin/awk -f function abs(val) { return val < 0 ? -val : val } ARGV[1] == FILENAME{ a[$1] = $2; } ARGV[2] == FILENAME{ … Read more
$ sed -nr ‘/Username/{n;s#.*>(.*)<.*#\1#p}’ file wipis_dxu Brief explanation, /Username/: find Username n: Read the next line of input s#.*>(.*)<.*#\1#p: extract the string between > … < 2 solved Grep a word from XML file with grep/sed
I think you are looking for this: awk ‘/^[JM]/{print $1,$2}’ i_ve_got_an_vi_edirtor_with_some_collums.file update Now i need the same but only for students that the surname starts from [A-D] awk ‘$2~/^[A-D]/{print $1,$2}’ i_ve_got_an_vi_edirtor_with_some_collums.file 16 solved Use awk to find letters and print results [closed]
If you can slurp whole input: perl -e’undef$/; $a=<>; print “$_\n” for $a=~m/(?:\b\S+\b\s+){5}your regexp(?:\s+\b\S+\b){5}/sg ‘ <input — 5 words of context. solved how to print n words of context while searching text [closed]
awk one liner awk ‘{if(NR>1)system(“grep -w ^”$2″ <file2>”);}’ <file1> Also many other solutions are there, check join or in awk itself without using grep, simply by storing the first files content in an array, it can be done, 1 solved bash: compare 2 files, then output third file with same pattern [closed]
You can use awk like this: awk ‘FNR==NR{a[substr($2,1,3)];next} substr($2,1,3) in a’ file1 file2 9 132185894 132209127 DUP 99 23234 3 solved How to find first three digits matching pattern from a single column between two text files [closed]
Note that foo=4/3 sets foo to the string 4/3. When that is printed via %f, ‘4/3’ is treated as 4; when that is printed with %s, it is printed as 4/3. If you want to evaluate the expression, you need it evaluated inside the script. For example: awk ‘END {printf “%f\n”, foonum/fooden }’ foonum=4 fooden=3 … Read more
Here is a solution that requires no subshell or external program, does not parse ls output (which is not recommended), and should work with filenames containing spaces (or even newlines). You can customize your prefix and extension. #!/bin/bash dir=”/path/to/files” prefix=”backup#” ext=”.tar.gz” max=1 for file in “$dir/$prefix”* do [[ $file =~ /$prefix([0-9]+)$ext$ ]] || continue n=”${BASH_REMATCH[1]}” … Read more
I am not going to do your homework for you! However I can give you some insight: store your 8 file names in an array call $RANDOM % 8 3 times and store the value in 3 index variables use the 3 index variables to extract your 3 files use sha256sum, sha512sum or md5sum to … Read more
The shell first processes input/output redirections like > 5 and attaches the relevant file handles to the file it opens (5 in this case). It also expands * into the matching files in the current directory. So what you end up with is: echo 2 <<ALL YOUR FILES>> is a valid inequality where the output … Read more
cat “73276948.sh” #!/bin/bash STR=”one two three” array=($STR) echo “${array[@]}” # prints: one two three echo “len: ${#array[@]}” # prints: len: 1 echo “1ST: ${array[0]}” # prints: one two three echo “2ND: ${array[1]}” # prints: one two three echo “3RD: ${array[2]}” # prints: one two three echo “Using loop:” for (( indx = 0; indx < … Read more
Based on answer of KamilCuk, its possible to output on follow way the line which is including the number of the active desktop: nr_of_active_desktop=activedesktop=$(wmctrl -d | grep “*” | rev | cut -d ‘ ‘ -f1) echo $nr_of_active_desktop solved How can I query the number of the virtual desktop on which the bash script is … Read more
Another way with awk: $ awk ‘{print s+=$1}’ file 2 6 13 10 15 13 solved Output subtotal at each line while adding up numbers, one per line