[ad_1] Use this: public void someMethod(int[] arr){ for(int i=arr.length-1; i >= 0; i–){ if(arr[i] <= 8){ arr[i]+=1; }else if(arr[i] ==9){ arr[i] = 0; } } } Refer https://docs.oracle.com/javase/tutorial/java/nutsandbolts/for.html for better undersatnding of for loop construct. [ad_2] solved (Java) Go thru array beginning at the last index [closed]
[ad_1] Try this. do{ System.out.print(“Please enter an integer or -1 to stop: “); input=Integer.parseInt(scan.nextLine()); boolean flag = true; for(int i=0; i<A.length; i++){ if(A[i].equals(input)) { System.out.println(“Duplicate input. Please enter another value: “); flag = false; break; } } if(!flag) { continue; } if(input != -1) //if input is Display.userInput(input); } while(input != -1); 1 [ad_2] solved … Read more
[ad_1] // Three-dimensional array. int[, ,] array3D = new int[,,] { { { 1, 2, 3 }, { 4, 5, 6 } }, { { 7, 8, 9 }, { 10, 11, 12 } } }; Which was taken from here, which I found using Google and searching with this string, “multidimensional arrays in C#”. … Read more
[ad_1] Use fgets to read the input string till you a reach a newline character (that means till the user hits enter). Then convert each character to int. #include <stdio.h> #include <stdlib.h> #include <string.h> int main() { int a[100], b[100], diff=0, m=0, n=0, temp[100], s=0,z,max=0; int iIndex=0; char cString[100]; int i=0; char* cpString=NULL; memset(&cString,0,100); printf(“Enter … Read more
[ad_1] From that, I want to get both the first and last non-null elements from the first and last rows each. 2D arrays are a pain in the ass, but they behave like one long array if you iterate them var w = array.GetLength(1); var h = array.GetLength(0); var a = array.Cast<int?>(); var ff = … Read more
[ad_1] A quick test shows that setting @jdweng’s purely LINQ solution 1X, a solution somewhat abusing LINQ to do indexing comes in at 7.4X and a solution using for comes in at 28.4X. (Ab)using LINQ with indexing: var c = Enumerable.Range(0, source[0].Length).Select(chpos => Enumerable.Range(0, source.Length).Select(si => source[si][chpos]).Join()).ToArray(); Using nested for loops: var sourcelen = source.Length; … Read more
[ad_1] It seems that calling $( ‘.none’ ).hide(); twice is unnecessary. Since this is the same type of functionality, add the same class to each of the elements for the click function. Then you want to match it to the list, one way to do this is through a matching attribute so it can be … Read more
[ad_1] Here’s a method using Array.forEach(): const number = 165; const candidates = [2, 42, 82, 122, 162, 202, 242, 282, 322, 362]; //looking for the lowest valid candidate, so start at infinity and work down let bestCandidate = Infinity; //only consider numbers higher than the target const higherCandidates = candidates.filter(candidate => candidate > number); … Read more
[ad_1] First, I think you want your input loop to look something like this – for (int x = 0; x < 10; ++x) { System.out.println(“Enter number: ” + (x + 1)); int num = scan.nextInt(); // <– get user input to // test. // Test for negative first. if (num < 0) { negativeList[neg++] … Read more
[ad_1] your supposed to create an array of intigers and pass it to the average function, and need to pass the size(so that you know how many times to loop). In the loop in your Average function add all the values to a temporary value, then divide by the count input-ed to the function. //returns … Read more
[ad_1] Try something like this: $data = //your array $html = “<table>”; foreach($data as $row) { $html .= “<tr>”; foreach ($row as $cell) { $html .= “<td>” . $cell . “</td>”; } $html .= “</tr>”; } $html .= “</table>”; Your question is extremenly vague so this is a vague answer, but you should get the … Read more
[ad_1] JTextField and String are not the same thing. You probably want to get the value from the text field like arrayWoord[0] = letterVeld1.getText(). Also, you should store the letterVelds in an array and just do for (int i = 0; i < 10; i++) arrayWoord[i] = letterVelds[i].getText(). [ad_2] solved Error: incompatible types
[ad_1] You have Jagged Array return type and you need to return two dimensional Rrectangular Array, You can return two dimensional array like this. public String[,] GetAllItems() { //your code String[,] xx = new String[arrayZise,2]; //your code return xx; } 1 [ad_2] solved String Array type method return type error [closed]
[ad_1] here’s how I would implement it: window.onload=function(){ var array1 = [1, 2, 3, 4, 5, 6] var array2 = [3, 4, 5, 6, 7, 8] var result = [] var resultCount=0; for (var i1 = 0; i1 < array1.length; i1++) { var comparedElement = array1[i1]; var isUnique = true; for (var i2 = 0; … Read more
[ad_1] You can flip the array, and check its length: echo count(array_flip($arr)); This works because an array index must be unique, so you end up with one element for every unique item in the original array: http://php.net/manual/en/function.array-flip.php If a value has several occurrences, the latest key will be used as its value, and all others … Read more