Introduction If you are looking for the most efficient way to get the smallest list, then you have come to the right place. In this article, we will discuss the various methods that can be used to get the smallest list possible. We will discuss the advantages and disadvantages of each method, as well as … Read more
Do like this Collections.sort(list, new Comparator<String>() { @Override public int compare(String o1, String o2) { return o1.length()-o2.length(); } }); 4 solved sort ArrayList using strin length [duplicate]
The reason your statement fails is that you are trying to access elements beyond the collection’s bounds. When iterating through programEvents, you are assigning indexes to evectr ranging from 0 to programEvents.Count inclusive. However, since indexing is zero-based, the index of the last element is actually programEvents.Count – 1; accessing programEvents[programEvents.Count] would throw an IndexOutOfRangeException. … Read more
If you are declaring list as ArrayList data = new ArrayList(); then you get the message about parameterizing the list because data can hold any Object If you know that you are going to add only strings in your list, declare it as ArrayList<String> data = new ArrayList<String>(); // pre java 7 ArrayList<String> data = … Read more
You want a Dictionary<>, e.g. Dictionary<Object, List<OtherObject>> Where Object is the Key and List<OtherObject> is the Value 2 solved A List of List and Object
Check the spelling. In your Cloud class it is rainning But in Sky class raining solved unexpected output is occurred [closed]
This is frankly as basic a question as it gets, and google could have helped you with this easily. Here’s your entire method if you want to design your own. public static int getCount(ArrayList A){ return A.size(); } solved How do I use on method to get the sizes of two different-sized arrayslists?
Besides the Map option, you can consider using some sort of Key value pair and, storing that in your array and sort your array based on the values. See this for potential key value pairs, or make your own. An example: package com.example; import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.util.List; public class KeyValue { … Read more
Try using foreach() for(Employee employee : employees()) { System.out.println(employee.name); } solved Incrementing a for loop over a List of java objects [duplicate]
private ArrayList<Student> readFile() throws FileNotFoundException { String fName = “p02-students.txt”; Scanner scan = new Scanner(new File(fName)); ArrayList<Student> studentList = new ArrayList<Student>(); while (scan.hasNext()) { String studentType = scan.next(); if (studentType.equals(“C”)) { studentList.add(readOnCampusStudent(scan)); } else { studentList.add(readOnlineStudent(scan)); } scan.nextLine(); } scan.close(); return studentList; } I didn’t get the error you mentioned earlier, but I was getting … Read more
After getting value from intent: ArrayList<String> arrayList = new ArrayList<String>(); valueaddlist = (Button) findViewById(R.id.valueaddlist); valueaddlist.setOnClickListener(new OnClickListener() { public void onClick(View v){ arrayList.add(product_id); arrayList.add(product_title); arrayList.add(product_image); arrayList.add(product_price); arrayList.add(product_desc); } valuedisplaylist = (Button) findViewById(R.id.valuedisplaylist); valuedisplaylist.setOnClickListener(new OnClickListener() { public void onClick(View v){ Intent intent = new Intent(this,AddedListProducts.class); intent.putStringArrayListExtra(“arrayList”, (ArrayList<String>) arrayList); startActivity(intent); } May be this will help you. In … Read more
Read the file sequentially – thats the easiest route. Then randomly shuffle the collection. Actually, another question. Could you use math.random() to look at the lines of the text file and if, lets say, the line 5 comes up then you remove it from the parameters you set for math.random()? It would pick from 0-9 … Read more
Write a program that takes an array/arraylist of integer and finds longest sub array/arraylist whose entries are equal [closed] solved Write a program that takes an array/arraylist of integer and finds longest sub array/arraylist whose entries are equal [closed]
Use a hashMap and check if this key already exists then update the double value by adding existing double value then put in the map. public static void main(String[] args) { List<MyObject> list = new ArrayList<MyObject>(); list.add(new MyObject(“a”,”b”,”c”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”e”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”c”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”d”,new BigDecimal(10.23))); Map<MyObject,MyObject> map = new HashMap<MyObject,MyObject>(){ @Override public … Read more
I tried to guess what exactly you’re trying to achieve. Assuming you’ve got an ArrayList containing Strings, the following code will probably do what you want to achieve (use the method updateList to change an ArrayList that looks like your first example into an ArrayList that looks like your second example): import java.util.ArrayList; import java.util.regex.Pattern; … Read more