My friend, you have a syntax error missing the key for that value: You are writing: @Element(name=”Video”, =false) and you are missing the “required” @Element(name=”Title”,required=false) solved Syntax error on token “,”, Identifier expected after this token [closed]
finger print security api https://developer.android.com/preview/api-overview.html ,its the new api introduced in 6.0 . Biometric Security – In an effort to enhance security, the much needed system-wide biometric fingerprint will be provided by Android Marshmallow. The user can unlock devices with fingerprints and purchase apps on Google Play 1 solved How can i scan my fingerPrint … Read more
Your class member model from class InputTab has never initialized. Therefore, you got a NPE at line model.requery();. That’s why you saved your data, but right after that, you got a NPE. You don’t need any Cursor in this class and, of course, you don’t need to requery() anything. 2 solved Nullpointer Exception in SQL, … Read more
You can change the status of the views programmatically. You should use view.setVisibility(View.GONE) if you want to remove the view from the layout, and view.setVisibility(View.INVISIBLE) if you want to hide it. To put them back , use view.setVisibility(View.VISIBLE). solved Hiding specific view in an activity
I think you’re implementing wrong Retrofit callback in your code. As I can see you’re receiving first a JSONObject called photos that contains a JSONArray photo, so your code should look like this Call<PhotoResult> call = apiInterface.getImages(query); call.enqueue(new Callback<PhotoResult>() {…} As you can see, the callback object is PhotoResult that is the root level of … Read more
String s = “http://example.com/GetJob.ashx?JobID=19358502&JobTitle=Factory%20Workers%20in%20Oldham%20-%20Immediate%20Start%20Now&rad=20&rad_units=miles&pp=25&sort=rv.dt.di&vw=b&re=134&setype=2&tjt=factory&where=oldham&pg=1&avsdm=2015-09-10T05%3a54%3a00-05%3a00”; s = s.substring(s.indexOf(“JobID=”) + 6); s = s.substring(0, s.indexOf(“&JobTitle”)); System.out.println(s); 3 solved How do i split the string of url link [duplicate]
I found that following this guide http://www.techrepublic.com/blog/software-engineer/a-comprehensive-troubleshooting-guide-for-androids-r-cannot-be-resolved-error/ solves the error. I’m not sure dough if “R cannot be found” is the exact cause of error. 1 solved The import android cannot be resolved
What else is in the GUI please show the complete GUI pic or the code you have tried You can use a textView add an ImageButton or Button both will do for setting the Background to the GUI use android:background=”@drawable/ur_background_name” in the Layout if you dont know about the layouts… then read This but here … Read more
do you mean two lines, each with a different style ? if so, use “fromHtml” , and add line-breaks. solved how do I create button like this in android with multiple text [closed]
Option 1: Step #1: Create your own style, by cloning one of the existing styles (from $ANDROID_HOME/platforms/$SDK/data/res/values/styles.xml), putting it in your own project’s styles.xml, and referencing it when you add the widget to a layout. Step #2: Create your own LayerDrawable XML resources for the RatingBar, pointing to appropriate images to use for the bar. … Read more
You can use universal image loader liabrary for loading image from server they provided good implementation for loading and caching image. Find it here solved Load Image from server and diaplay in listview [duplicate]
You shouldn’t use == to compare Strings in Java. Use t1.toString().equals(t2.toString()) instead. 4 solved if(…) – two equal sides are considered as not equal [duplicate]
RadioGroup radioGroup = (RadioGroup) this .findViewById(R.id.radio_group); radioGroup .setOnCheckedChangeListener(new RadioGroup.OnCheckedChangeListener() { @Override public void onCheckedChanged(RadioGroup radioGroup, int id) { final RadioButton radioButton = (RadioButton) radioGroup .findViewById(id); String selectedText = radioButton.getText().toString(); Intent i = new Intent(this, PersonData.class); i.putExtra(“cakedata”, selectedText); startActivity(i); } }); solved How to send data to new Android activity
You have an error concatenating your SQL statement: String selectQuery = “SELECT * FROM ” + TABLE_MURIDD + “ORDER BY” + COLUMN_NOMOR + “ASC”; should be: String selectQuery = “SELECT * FROM ” + TABLE_MURIDD + ” ORDER BY ” + COLUMN_NOMOR + ” ASC”; EDIT: (Thanks to Michael Dogg) A better way of protecting … Read more
You could parse XML or use regex. To keep things simple, I would suggest regex. Here is how you can use it: Pattern pattern = Pattern.compile(“<span id=\”artist\”>(.*?)<\\/span><span id=\”titl\”>(.*?)<\\/span>”); Matcher m = pattern.matcher(input); if (m.find() { MatchResult result = m.toMatchResult(); String artist = result.group(1); String title = result.group(3); } Where input is the XML you have. … Read more