Well the loop seems to be this one (at the end of the code):
for i,j in itertools.combinations([a,b,c],2):
all_diffs=alldiffs(i,j)
total=count_total(i,j)
zero=count_zero(all_diffs)
total=np.array(total)
union=map(sub,total,zero)
zero=np.array(zero).tolist()
union=np.array(union).tolist()
union=[list(x) for x in union]
sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \
for (aa, bb) in itertools.izip(zero, union)]
sim_comb=sum(sim,[])
sum_of_sim=sum(sim_comb)
number_sum=len(sim_comb)
ave=sum_of_sim/number_sum
one_ave=1-ave
print one_ave
One possible solution would be to write:
output = []
for i,j in itertools.combinations([a,b,c],2):
all_diffs=alldiffs(i,j)
total=count_total(i,j)
zero=count_zero(all_diffs)
total=np.array(total)
union=map(sub,total,zero)
zero=np.array(zero).tolist()
union=np.array(union).tolist()
union=[list(x) for x in union]
sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \
for (aa, bb) in itertools.izip(zero, union)]
sim_comb=sum(sim,[])
sum_of_sim=sum(sim_comb)
number_sum=len(sim_comb)
ave=sum_of_sim/number_sum
one_ave=1-ave
output += [one_ave]
print output
1
solved Python: How to store for loop result in a list? [duplicate]