var x = 6; var y = 4; var a = function(b) { return function(c) { return y + b + c; } }; x = 2; y = 5; // unnecessary, meant to confuse var fn = a(x); // creates a closure, where b equals 2 x = 1; // unnecessary, meant to confuse … Read more
Your code based on Android Dev Guide is working, to be more precise, this one: alarmMgr = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE); Intent intent = new Intent(context, AlarmReceiver.class); PendingIntent alarmIntent = PendingIntent.getBroadcast(context, 0, intent, 0); alarmMgr.setExact(AlarmManager.ELAPSED_REALTIME_WAKEUP,SystemClock.elapsedRealtime() + 10 * 1000, alarmIntent); Alarm.Receiver.java: public class AlarmReceiver extends BroadcastReceiver { @Override public void onReceive(Context context, Intent intent) { /* class1 = … Read more
Try: select date(event_start), min(time(event_start)), max(time(event_start)) from t group by date(event_start) order by date(event_start) solved Get min and max time section
That happen because of new android version 9.In android 9 user can enable and disable particular permission in app settings. for that you have to handle run time permission. You have to handle runtime permission in app then upload apk again in play store once google approve it App will come again live. while uploading … Read more
Hey just remove attr_accessor :password from model. It works class User include Mongoid::Document attr_accessor :password//remove this line field :name, type: String field :category, type: String field :email, type: String field :password, type: String validates :name, presence: true ,format: { with: /\A[a-zA-Z]+\z/} validates :email, presence: true , format: { with: /\A[\w+\-.]+@[a-z\d\-.]+\.[a-z]+\z/i } , uniqueness: { case_sensitive: … Read more
I think you need aggregation by sum: df3 = df2.groupby(‘Destination Address’, as_index=False)[‘Aggregated Event Count’].sum() Sample: df2 = pd.DataFrame({‘Destination Address’:[‘a’,’a’,’a’, ‘b’], ‘Aggregated Event Count’:[1,2,3,4]}) print (df2) Aggregated Event Count Destination Address 0 1 a 1 2 a 2 3 a 3 4 b df3 = df2.groupby(‘Destination Address’, as_index=False)[‘Aggregated Event Count’].sum() print (df3) Destination Address Aggregated Event … Read more
send data from inputAddrss, Intent intent = new Intent(getBaseContext(), SignoutActivity.class); intent.putExtra(“url”, YOUR_EDIT_TEXT.getText().toString()); startActivity(intent); receive data in MainActivity, String s = getIntent().getStringExtra(“url”); then load into webview view.loadUrl(s); solved webview load url from input text in another class [duplicate]
We can do it via Array.map() const data = [[11,12,13,14],[21,22,23,24],[31,32,33,34],[41],[43],[51]] let result = data.map(d => { if(d.length < 2){ return d[0] } return d.at(0) +’ -‘ + d.at(-1) }) console.log(result) solved How to modify multidimensional array? [duplicate]
You are on the right track to setup the delegate. In Storyboard: create a Segue of type Embed Segue from the ContainerView to the ViewController to embed. Select the segue and set a Identifier. In Code, in prepareForSegue(): Set the myContainerView propert Set the delegate class ViewController: UITableViewController, ContainerViewDelegate { var myContainerView:ContainerView? // we do … Read more
SELECT DISTINCT A.EMPLOYEENAME FROM Attendance AS A JOIN Attendance AS B ON B.LEAVE_DATE = A.LEAVE_DATE + 1 AND B.EMPLOYEENAME = A.EMPLOYEENAME JOIN Attendance AS C ON C.LEAVE_DATE = B.LEAVE_DATE + 1 AND C.EMPLOYEENAME = B.EMPLOYEENAME The inner joins will remove all employee who were not absent three consecutive days. 14 solved Find out the Employees … Read more
The API is confusing: What is namelen ? is it the length of the initial prefix of name that is the name of the student? In this case you should allocate one extra byte for the null terminator and copy the name appropriately. is it the maximum length for the student name? Again if this … Read more
Get all column values to one row and find the count SQL SERVER ;WITH CTE AS ( SELECT COL1 Name FROM YOURTABLE UNION ALL SELECT COL2 FROM YOURTABLE UNION ALL SELECT COL3 FROM YOURTABLE UNION ALL SELECT COL4 FROM YOURTABLE UNION ALL SELECT COL6 FROM YOURTABLE UNION ALL SELECT COL7 FROM YOURTABLE ) SELECT DISTINCT … Read more
This line of code: string checkuser = “select * from tb_Login where Username=”” + txtUsername.Text + “” and Password='” + txtPassword.Text + “‘ “; Is sending a query to the database and asking: “Give me all the columns from tb_Login whose UserName is the value in the txtUsername box and the Password is in the … Read more
The following algorithm can me implemented with O(N+M) complexity. Take any vertex u. Use flood fill algorithm to reach other vertices. If any vertex is not reachable, return NOK. Now do the same, but go to the opposite direction. If any vertex is not reachable, return NOK. Return OK. (Here we know that there is … Read more
if you write in header file static PFNGLGETERRORPROC glGetError; every c/cpp have own private copy of glGetError and it not conflict with other because it static – so different cpp files use different versions of glGetError – in one cpp unit you init one version and it !=0, when you enter to another cpp unit … Read more