create data module class as below class Data { var text:String? } then add 100 objects in array and load tableview from array. Now create custom cell & take reference of textfield in custom cell class. Implement observer for text change on textField in this class. Now write function as below in custom cell func … Read more
You are not using the result of query IQueryable<StammdatenEntityModel> query = dbSet; query = query.OrderByDescending(s => s.CreateDateTime); query = query.Where(s => s.Deleted == false); if(!String.IsNullOrEmpty(keyword)) { query = query.Where(s => s.SerialNumber.Contains(keyword)); //simplified for SO } query = query.Skip(skip); query = query.Take(take); 0 solved IQueryable with Entity Framework – order, where, skip and take have no … Read more
The two likely problems that I can see without you adding the error code. is that you are missing the column names in your insert statement. is that a user is putting an apostrophe in one of your text boxes. This is a SQL Injection vulnerability. Try something similar to this instead: using (SqlConnection con … Read more
[EDIT]The question was updated and the below was answered based on the original question. if you fix your input var1 then you can do something like this: var1 = ‘{“text”:”tool”,”pos”:”\\xd1\\x81\\xd1\\x83\\xd1\\x89\\xd0\\xb5\\xd1\\x81\\xd1\\x82\\xd0\\xb2\\xd0\\xb8\\xd1\\x82\\xd0\\xb5\\xd0\\xbb\\xd1\\x8c\\xd0\\xbd\\xd0\\xbe\\xd0\\xb5″}’ md = {} for e in var1[1:-1].split(‘,’): md[e.split(‘:’)[0][1:-1]] = e.split(‘:’)[1][1:-1] md[‘pos’] = (bytes.fromhex(”.join([h for h in md[‘pos’].split(‘\\x’)]))).decode(‘utf-8’) print(md) output: {‘text’: ‘tool’, ‘pos’: ‘существительное’} 2 solved … Read more
You can use the background-attachment:fixed CSS property to achieve this. A very quick demonstration can be seen below: html, body { margin: 0; padding: 0; } html { background: url(http://lorempixel.com/800/600); background-attachment: fixed; /*This stops the image scrolling*/ } body { min-height: 100vh; margin-top: calc(100vh – 100px);/*Only 100px of screen visible*/ background: lightgray;/*Set a background*/ } … Read more
Create an .rc file to refer to the desired embedded .exe as an RCDATA resource, eg: MYEXE RCDATA “path\to\file.exe” Add the .rc file to your project. The referred .exe file will then be compiled into your final executable. You can then access the MYEXE resource at runtime using the Win32 FindResource()/LoadResource()/LockResource() functions, or higher-level framework … Read more
Data needs to be an object. Example: stop: function(){ $.ajax({ type: “POST”, data: {name: name, lastname: lastname}, url: “ajax.php”, }); } In case of form could be: data: $(‘#form’).serialize(); 0 solved How to get data from ajax? [closed]
Below is the solution for your problem: import java.util.*; import java.lang.*; class Rextester { public static void main(String args[]) { String str = new String(“kyc_CWaccountOperatorName|DANIYAL,kyc_cnic_ind|9110129505705,kyc_fatherName|Abujan,kyc_motherMaidenName|MOTHER,kyc_CWmobileNumber|03312551746,kyc_CWdateOfBirth|20/02/1993,kyc_cnicDateOfExpiry|2027-02-20,kyc_CWplaceOfBirth|KHI,kyc_mailAddHouseFlat No|Dha,kyc_city|Abbottabad”); String[] ar = str.replace(“|”,”=”).split(“,”,0); for(String s : ar) System.out.println(s); } } You can check output on the below link: https://ideone.com/kzBYfl 1 solved how to get value from string in … Read more
Your point structure does not match up with your sentence. So I’ll answer: To reach level 2 50 XP is needed. To reach level 3 a further 55 XP is needed. To reach level 4 a further 60 XP is needed and so forth. <?php $get_level = function () { foreach (range(0, 300, 50) as … Read more
I’m not entirely sure what you’re doing, but you could do something along these lines to enforce an agent to use particular security. var protocol = require(‘https’); var configuration = { hostname: ”, port: 443, path: ”, method: ”, secureProtocol: ‘TLSv1_2_method’ } protocol.request(configuration, context => { // Request information such as body. }); Not sure … Read more
You should use next code: JSONArray jsonArray = new JSONArray(response); JSONObject jsonObject = jsonArray.getJSONObject(0); Log.d(“ID -> “, jsonObject.getString(“id”)); Log.d(“CAT -> “, jsonObject.getString(“cat”)); Because you have not an object in json, but an array, so you should create array instead of object. And thats why your modification works. Because in modified code “data” is an object … Read more
Is that what are you looking for? for(var i=0 ; i<15;i++) { var input = document.createElement(‘input’); input .setAttribute(‘id’,”input”+i); document.getElementById(“formName”).appendChild(input); } 3 solved How to generate 15 inputs with loop for and run just once? [closed]
Because count would reset to 0 on every iteration of the loop (also count would no longer be visible after the loop)! But, you don’t need count in the first place (since you have i and count is effectively i + 1 – and would be three after loop) – for (int i=0; i<5; i++) … Read more
It would be something like this on your model: def self.pending_count where(status: 0).count end def self.in_progress_count where(status: 1).count end def self.finished_count where(status: 2).count end Then you can just call Model.pending_count (or the other methods) wherever you need it. solved How to find out the number of records in a table? [closed]
There are some problems with your code, but let’s look at the output first. You get that output, because you are not calling the function that you defined: print(“The lenght of the hypotenous is”,findhypot) So instead of just putting findhypot in your print you should call it and pass the two paramters that you just … Read more