What is the cause of “It seems that this project has not been built yet. Do you want to build it now?” message when compiling using Codeblocks? [closed] solved What is the cause of “It seems that this project has not been built yet. Do you want to build it now?” message when compiling using … Read more
You have several problems with your code, neither of which has to do with accessing this. First, you have ths arguments in the wrong order in the callback. The first argument is the element, the second is the index (maybe you’re used to jQuery — it uses the opposite order in its .each() and .map() … Read more
The browser DOES NOT convert pre-processed (LESS, SCSS, Compass) CSS rules. You need to use a build script/compiler BEFORE linking a normal CSS file to your HTML. This process converts SCSS/LESS -> CSS for your browser to render. You can use Webpack, Grunt, Gulp, or even desktop/GUI tools to do this. You can also use … Read more
It seems, your original photo contains EXIF metadata records. Among others, it can contain additional instructions how to process the image before being shown. Some apps/SDKs do respect that instructions, others silently ignore EXIF – this is why you can receive such thing as mirroring etc. EXIF orientation values There are 8 possible EXIF orientation … Read more
list_sum_recursive doesn’t return a list; it returns the sum of the values in its argument: list_sum_recursive([]) == 0 list_sum_rescursive([1]) == 1 + list_sum_recursive([]) == 1 + 0 == 1 list_sum_rescursive([1, 2]) == 1 + list_sum_recursive([2]) == 1 + (2 + list_sum_recursive([])) == 1 + (2 + 0) == 1 + 2 == 3 If you … Read more
Existing Delphi code translation: public static string ByteToHex(Byte InByte) { char[] Digits = new char[] { ‘0’, ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, ‘6’, ‘7’, ‘8’, ‘9’, ‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, }; return string.Concat(Digits[InByte >> 4], Digits[InByte & 0x0F]); } Better implementation (all you want is formatting): public static string ByteToHex(Byte InByte) => InByte.ToString(“X2”); … Read more
So you need a bit of math… In theory you need to draw a line from P3 to point X which lies between P1 and P2. The vector between P1 and X is actually a projection of P3-P1 to a line described by P1 and P2. So: X = P1 + (P3-P1)*((P2-P1)/(|P2-P1|)) * ((P2-P1)/(|P2-P1|)) To … Read more
Javascript has asynchronous operations. But, a for loop is synchronous, not asynchronous. The code you show doesn’t use any asynchronous operations, therefore it’s all synchronous. Should myfunc() execute in node and take longer, so that “end” should be invoked earlier because javascript is asynchronous? No. Nothing in myfunc() is asynchronous. That’s all synchronous code in … Read more
You can use exceptions. Try this: DECLARE y NUMBER; b emp.ename%TYPE; BEGIN y := :enter_no; SELECT ename INTO b FROM emp WHERE empno = y; EXCEPTION WHEN NO_DATA_FOUND THEN DBMS_OUTPUT.PUT_LINE(b); END; 0 solved VALUE NOT EXIST (SQL)
Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there should be no if solved Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there should be … Read more
. It’s working fine when I pass 10-15 input but taking more than 5 minutes for 30 input. I need to make it work for 100 inputs solved . It’s working fine when I pass 10-15 input but taking more than 5 minutes for 30 input. I need to make it work for 100 inputs
This will work, take the form element of jquery-steps.call remove on that. $(“#formid”).steps(“remove”, 5); where the form tag contains h1 and fieldset’s and for ex formid is the id of form. solved Unable to skip the Jquery-step
Arrays are 0-indexed, This means that the last element of an array is not at array.length but at array.length – 1. You’ll have to create a new array (sub-array) and then start adding elements to it. Your code should be like this: var divs = []; for (var x = 0; x < nodeArray.length; x++) … Read more
Wrap your simply value inside an Observable “Everything is a Stream” Observable.of(yourValue).switchMap(yourSwitchMapFunction) @pixelbits the constructor of a Subject doesn’t have any parameter, and less a value, since the productor of values of the Subject are outside the stream, if you want to use a Subject you need to do something like this: const mySubject = … Read more
The splitter() function here does the job you ask for. It takes quite a lot of arguments, unfortunately. There’s the value to be split (value), the size of the chunk at the least significant end of the value (p1), the size of the middle chunk (p2), and then pointers to the high, medium and low … Read more