[Solved] I am getting error while loading linktext.com from SQL with help of PHP [closed]

I would have a guess that you need escape the quotes or use single quotes in your SQL. I would have a stab and say your code is outputting an incorrect format for the links. $url=”<a href=”https://stackoverflow.com/questions/46113161/link.com”>link.com</a>”; ## << This is the value from the database echo $url; As you can see there are too … Read more

[Solved] Condition is not evaluated in loop

Initially you set: int menu_choice = 0; Then you ask: if (menu_choice < 1 || menu_choice > 4 ) The choice is smaller than 1 so the if block is entered. You then get some user input and exit the application. 3 solved Condition is not evaluated in loop

[Solved] Beginner: Objective C errors in XCode

I saw a couple of errors: #import “RadioStations.h” ….. // Change newName to name. (like in header says) // Change this – (NSString*)newName{ – (NSString*)name{ return name; } …… – (void)setFrequency: (double)newFrequency{ frequency = newFrequency; } // This must be delete } @end solved Beginner: Objective C errors in XCode

[Solved] How can I avoid SQL injection in my code below? [duplicate]

As suggested, prepared statements are the best way to achieve good protection from SQL injection. Shortened Example You will need to add entries to fill in all columns you wish to insert. $email = $_POST[‘e-mail’]; $fn = $_POST[‘firstname’]; $ln = $_POST[‘lastname’]; if ($stmt = $mysqli->prepare(“INSERT INTO `newcartdb`.`orders`(Email,Firstname,Lastname) values(?,?,?)”) { $stmt->bind_param(“sss”, $email, $fn, $ln); “sss” – … Read more

[Solved] SQL – Select all row that exist between two dates [closed]

I think this should work. I used :start and :end as placeholders for your input values. The query selects all employees with their working dates when the working date is at least partially part of your input range. Visualization (I: input range, y: selected, n: not selected): ——–IIIIIIIIIIIIIIIIIIII———- –nnn-yyyy—yyyy———yyyyy—-nn- Query: SELECT * FROM workdates WHERE … Read more

[Solved] HTML Symbol for following symbol

the code &#10147; is probably as close as you’ll get (it’s for a right-pointing arrow, I don’t know the code for the corresponding left=pointing one, but one may exist) In any case, you could always transform it using rotateY like so: (EDIT: &#x27A4; also close, but right-pointing also) .arrows { -ms-transform: rotateY(180deg); /* IE 9 … Read more

[Solved] Add 1 Day to a Date [closed]

The most reliable way to get the next occurrence of a time is nextDate(after:matching:matchingPolicy: of Calendar because it considers also daylight saving changes. assuming datePicker is the NSDatePicker instance: let date = datePicker.date let calendar = Calendar.current // get hour and minute components of the given date let components = calendar.dateComponents([.hour, .minute], from: date) // … Read more

[Solved] VBA Macro that gets range of rows in column A and replace them with values in column B

Answer for your question Sub Test() Dim RangeX As Variant RangeX = InputBox(” Enter Range of rows. For Example rows 3 & 4 Means 3-4″) Row1 = Left(Trim(RangeX), 1) Row2 = Right(Trim(RangeX), 1) For i = Row1 To Row2 Cells(i, 1).Value = Cells(i, 2).Value Cells(i, 3).Value = “Values Replaced” Next MsgBox “Process Completed” End Sub … Read more

[Solved] i have to get result like bellow – from two arrays in javascript [closed]

var array1 = [“2017-07-23_30-12-98″,”2016-06-23_13-12-23″,”2017-05-20_30-12-43″,”2015-02-23_30-12-98”]; var array2 = [“2017-07-23_30-12-98″,”2014-06-23_13-12-94″,”2015-05-20_30-12-98″,”2015-02-23_30-12-98”]; console.log( array1.reduce((obj, s) => { if(array2.indexOf(s) !== -1) { obj.matched.push(s); } else { obj.unmatched.push(s); } return obj; }, {matched: [], unmatched: []}) ) solved i have to get result like bellow – from two arrays in javascript [closed]