[ad_1] As you’ve noticed, if you follow this path you’ll end up with some really unwieldy names. Naming is largely up to preference (for personal or new projects) or convention (for existing projects). If you want to go learn a convention, read some code that you might want to contribute to. Most importantly, though, be … Read more
[ad_1] You could just get the div element you want the code to be in, and then set the innerhtml to <script>your code here</script> EDIT: Try assigning your function like so: var myFunc = function() { //Code } Then you can call myFunc(parameters) 3 [ad_2] solved How to add local variables and a different function … Read more
[ad_1] go to on this URL and read it http://blog.sqlauthority.com/2009/04/13/sql-server-introduction-to-joins-basic-of-joins/ I think it is very helpful to understanding join in SQL… [ad_2] solved how to join two table in sql [closed]
[ad_1] You’ll want to take a look at the UIImagePickerController class which is what lets you access the camera functions of your iOS device. Specifically, you’ll want to use the source type UIImagePickerControllerSourceTypeCamera (first checking if the device has a camera via isSourceTypeAvailable:), with media type kUTTypeImage, present the camera controller via presentViewController, and you … Read more
[ad_1] == tests for reference equality. .equals tests for value equality. Threfore you should use: if (lista.getString(0).equals(“username”)) See How do I compare strings in Java? [ad_2] solved condition == between string and constant [duplicate]
[ad_1] if you want to split it in a list of strings then you can use String.Split function. string[] splitted = str.Split(‘,’); [ad_2] solved How to use Substring function in C# [duplicate]
[ad_1] So you have the following: if(condition1){ block1; } if(condition2){ block2; }else{ block3; } To disable/ignore the second if you can either use an else if statement: if(condition1){ block1; } else if(condition2){ block2; }else{ block3; } Or a return statement after block1 if(condition1){ block1; return; } if(condition2){ block2; }else{ block3; } 4 [ad_2] solved The … Read more
[ad_1] Ok, this will get you just started with the basics, but you’ll have to figure out the logic of your math, the various index values, and order of operations to solve your problem. This simply opens a file and displays its contents. The data is read as strings, and converted to floats so that … Read more
[ad_1] this help you : <!DOCTYPE html> <html> <head> </head> <body> <br> <form name=”test”> input<br><br> <input type=”number” name=”x1″ id=”x1″ style=”width:70px”> X * <input type=”number” name=”y1″ id=”y1″ style=”width:70px”> Y <br><br> <input type=”button” name=”Solve” value=”Solve” onclick=”myFunction()” ><br> <br><br> OutPut =<output type=”number” name=”x” id=”x” style=”width:100px”></output> <br><br> <p id=”info”></p> </form> <script type=”text/javascript”> function myFunction() { var x1 = document.forms[‘test’][“x1”].value; … Read more
[ad_1] You need a mechanism to input text from a source e.g. keyboard or command-line etc. Given below are some examples: From keyboard: import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(“Enter a text: “); String s = scanner.nextLine(); for (int i = s.length() – 1; … Read more
[ad_1] Php is a programming language not a database. You do not need a database for a slideshow, however you would use php to upload the images as well as list all the images in a directory. Once you accomplish that, you can pass the images to your slideshow. You can probably easily implement this … Read more
[ad_1] Not all browsers utilize the same rendering engine or follow the same rules. This is why they all look different in your case. The Opera browser actually adheres to the HTML guidelines the best. Unfortunately, they wont always all render the same and it’s a constant issue for developers. I would use strict CSS … Read more
[ad_1] Your syntax doesn’t allow for that result. If the first if loop evaluates to true, then the second must be false, and vice-versa. And since the code within the if loops sets one value to safe and the other to busted, this will always be the case. I assume that it’s a blackjack style … Read more
[ad_1] I would start by writing down everything you know about crime. For example:Police, Detectives, Locations, CrimeType, Crime Instance etc. Theses could be your tables. Link the data in the tables to make it into a database. The data in the tables may be something like: Location: Name, Address, Type, creationDate, user Crime: Name, Severity, … Read more
[ad_1] var lstPnts = new List<PointF>(); lstPnts.Add(new PointF(23.92f, 6)); lstPnts.Add(new PointF(23.88f, 0)); lstPnts.Add(new PointF(0, 0)); lstPnts.Add(new PointF(0, 6)); var avgPoint = new PointF(lstPnts.Average(t=>t.X),lstPnts.Average(t=>t.Y)); var ordered = lstPnts.OrderBy(t => Math.Atan2(avgPoint.Y – t.Y, avgPoint.X – t.X)).ToArray(); We found an average point. Then we calculated the angle between mid point and the other points and sorted our array … Read more