[Solved] initialization of char [] and working with it. I don’t want to use “string” [duplicate]
OK if you want to fill your char with ‘b’ character you CAN do it this way char d[7]; int i; for (i = 0; i < 7; i++) { d[i] = ‘b’; } solved initialization of char [] and working with it. I don’t want to use “string” [duplicate]