[ad_1] Change your jQuery selector to $(‘.selectedoptionselect’) The value of the select will be whatever option is selected. [ad_2] solved Create array with values of multiple select dropdown options [closed]
[ad_1] In pigstorage P and S should be capital letter. change like this it will work. STORE data INTO ‘tmp/data’ USING PigStorage(‘|’); 1 [ad_2] solved STORE GIVING ERROR when we use PIGSTORAGE
[ad_1] Try changing from this : $result = mysql_query(“SELECT email FROM subscribers WHERE email=””.$_POST[“email’].”‘”;); $num_rows = mysql_num_rows($result); if(isset($_POST[‘submit’])){ if($_POST[’email’]!=””){ if ($num_rows > 0) { echo “email already unsubscribed”; } else { $update_sql = “UPDATE subscribers SET unsubscribed = ‘1’ WHERE email=””.$_POST[“email’].”‘”; mysql_query($update_sql, $connection); echo “<div id=’notify’ style=”margin-left: auto; margin-right: auto; width: 330px; height: 40px; text-align: … Read more
[ad_1] from collections import defaultdict d = defaultdict(list) for i,j in enumerate(x): d[j].append(i) Using defaultdict with the default being empty list and enumerate to provide the index [ad_2] solved Python: build dictionary from list
[ad_1] Try stringOne .filter(function(el) { return el !== “”; }) .join(” – “); The filter gets rid of all elements that are empty, join should be straightforward. 1 [ad_2] solved Logically concatenating strings separated by hyphens
[ad_1] I’d rather write a more useful and correct version of this code #include <stdio.h> int main() { int n1, n2, ans; char op; scanf(“%d %c %d”, &n1, &op, &n2); switch (op) { case ‘+’: ans = n1 + n2; break; case ‘-‘: ans = n1 – n2; break; case ‘*’: ans = n1 * … Read more
[ad_1] Consider the case when you insert at the end of the list. Then you get // current = NULL current->next = nextnode; // is ((struct node*)NULL)->next = nextnode; [ad_2] solved I am getting Segmentation fault (core dumped) for below code.Please help me out [closed]
[ad_1] You’re getting no relevant answers on Google because the answer is (d): None. The closest kinds of joins are left-join and right-join. 3 [ad_2] solved Types of SQL joins
[ad_1] For anyone curious, I quickly wrote a function for it. First off, the complete matching is written as a 2D list. The following function is needed before writing the main one: def index_2d(myList, v): #Returns tuple containing the position of v in the 2D list for i, x in enumerate(myList): if v in x: … Read more
[ad_1] First of all you want to show user data (name etc.), so select from user. You want to show their friends status related to user 1 with it, so join accordingly. As they can have a friends status related to user 1 or not, but you want to show them anyway, you cannot use … Read more
[ad_1] No statements will be executed after return you are returning inside whlie while($row = mysql_fetch_array($query)){ return $row[name];// this is wrong } Change it to $name = array(); while($row = mysql_fetch_array($query)){ $name[] = $row[name];// assign to array } return $name;// <— return here. Also switch to mysqli_* or PDO as mysql_* is deprecated. [ad_2] solved … Read more
[ad_1] Restate problem: 1) Compute F = largest proper factor of X 2) Output X-F Instead of directly searching for the largest proper factor, apply three trivial optimizations (maybe something more advanced will be needed, but first see if three trivial optimizations are enough). A) Find S = smallest factor of X greater than 1. … Read more
[ad_1] The answers in the comments are more pythonic, but if you want a more easily understandable example >>> books = {} >>> line = “Calculus | James Stewart” >>> parts = line.split(‘|’) # can also do title, author = line.split(‘|’) >>> books[parts[0].strip()] = parts[1].strip() >>> print(books) {‘Calculus’: ‘James Stewart’} 1 [ad_2] solved How can … Read more
[ad_1] If you want to catch all strings containing only upper and lowercase characters, periods and spaces, you can use ^[a-zA-Z\. ]+$ Here’s a breakdown of how the regex works ^ matches the beginning of the string [a-zA-Z\. ] matches any character a-z, A-Z, or a period or space + makes the above match any … Read more
[ad_1] You have not set the tag on the view , do convertview.setTag(holder) … if(convertView == null) { convertView = inflater.inflate(R.layout.style_row, null); holder = new ViewHolder(); holder.txtTitle = (TextView) convertView.findViewById(R.id.txtAbout); holder.txtContent = (TextView) convertView.findViewById(R.id.txtDetail); convertView.setTag(holder) } Your code seems fine , problem might be that you are requesting multiple times from your code on the … Read more