[Solved] I have a string in javascript. I need to pick all strings between “{” and “}”

Use regular expression /{(.*?)}/g: var re = new RegExp(‘{(.*?)}’, ‘g’); result = re.exec(‘QUO-{MM/YYYY}-{SERVICEGROUP}’); Will output: [“{MM/YYYY}”, “MM/YYYY”] Edit: ‘QUO-{MM/YYYY}-{SERVICEGROUP}’.match(/{(.*?)}/g); Will output: [“{MM/YYYY}”, “{SERVICEGROUP}”] 4 solved I have a string in javascript. I need to pick all strings between “{” and “}”

[Solved] How do I track when a link is clicked? [closed]

The following code will get you started. Check out this fiddle. Here is the snippet. var points = 0; $(“a.ad”).click(function() { points++; //send point to server //tell the user about the increase in points alert(points); }); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <a class=”ad” target=”_blank” href=”http://www.google.com”> This is Ad</a> <br> <a target=”_blank” href=”http://www.google.com”> This is Not an Ad</a> 3 … Read more

[Solved] Java: Combining the inputs of a while loop

Here is the code together with some comments. import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; //import java.util.Scanner; public class Ingredients { public static void main(String [] args)throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); //or Scanner scan = new Scanner(System.in); int ingredientID=0; int sumOfIngredients=0; System.out.println(“Keep selecting the ingrients that you want until … Read more

[Solved] Click and drag option (JAVA)

To automate mouse clicks, holds and moves you can look into the Robot Class This is the basics of a mouse click: where x and y is the coordinate of the point on the screen in pixels where you want to click. public static void click(int x, int y) throws AWTException{ Robot bot = new … Read more

[Solved] Can someone run malicious code while writing into .txt

Writing to a text file doesn’t introduce any direct attack vectors. It is possible to write flawed code to write to a text file which introduces attack vectors (particularly if you accept a file name as user input). Things you do with the text file later (such as making it public with certain content-types) might. … Read more

[Solved] Palindrome Checker for numbers

The easiest way to check if a number is a palindrom would probably to treat it as a string, flip it, and check if the flipped string is equal to the original. From there on, it’s just a loop that counts how many of these you’ve encounteres: begin = int(input(‘Enter begin: ‘)) end = int(input(‘Enter … Read more

[Solved] how to verify if html5 is supported by the browser [closed]

First thing- As long as your HTML5 is valid, browsers render most of the times correctly. Check it – https://validator.w3.org/ Secondly- Check if there are any issues in your console. Make your JS error free and CSS non-overlapping. Lastly- There are some frameworks that you can use like – Selenium or PhantomJS or ZombieJS etc., … Read more

[Solved] for each element with this id jquery

Id should be unique, use a class instead. <input class=”path”/> <input class=”path”/> $(‘.path’).val(“123”); And when you are setting a common value by using a class selector, there is no need to iterate. solved for each element with this id jquery

[Solved] Change label/button text depending of the bool status

You can access your form elements by their Name property. For example if you have a button named button1, you can edit its Text property like this: button1->Text = “new name”; It’s the same for labels, text boxes and many other elements. About the bool status you say, I don’t know what are you trying … Read more

[Solved] Get css class list from style tag

Below code helped me getting my requirement. var resultarray = []; var a = $(‘#pageStyleCss’).html(); if (a != undefined) { while (a.indexOf(‘{‘) != -1) { resultarray.push(a.substring(0, a.indexOf(‘{‘))); a = a.substring(a.indexOf(‘}’) + 1); } } var i, option = “<option value=””></option>” for (i = 0; i < resultarray.length; ++i) { if (resultarray[i].indexOf(‘.’) > -1) { option … Read more

[Solved] Print elements of list horizontally [closed]

Here’s a silly one-liner version: def print_table(seq, width=3): print(‘\n’.join([”.join( [(str(u[-i]) if len(u) >= i else ”).rjust(width) for u in seq]) for i in range(max(len(u) for u in seq), 0, -1)])) And here’s the same algorithm in a somewhat more readable form: def get_cell(u, i): return str(u[-i]) if len(u) >= i else ” def print_table(seq, width=3): … Read more