Kirat[ad_1] If you want it static you will have to do it like this: public static Vecteur somme(Vecteur v1, Vecteur v2) { Vecteur u = new Vecteur(v1.x + v2.x, v1.y + v2.y, v1.z + v2.z); return u; } The only way to do it with just one parameter and being able to use your own … Read more
[ad_1] I’ve tried this, looking at wikipedia. http://en.wikipedia.org/wiki/Invertible_matrix#Blockwise_inversion getInverse <- function(mat) { if(nrow(mat) == 1) { return (matrix( 1.0/ mat[1,1] )) } idx <- nrow(mat) / 2 A <- mat[1:idx, 1:idx, drop=F] B <- mat[1:idx, -1:-idx, drop=F] C <- mat[-1:-idx, 1:idx, drop=F] D <- mat[-1:-idx, -1:-idx, drop=F] invA <- getInverse(A) temp <- getInverse(D – C … Read more
[ad_1] Your solution is has O(n^2) time complexity – those nested loops will be very slow for large lists. However, with the aid of a HashMap, an O(n) solution is possible. Map<String, NameAndValue> map = new HashMap<>(); for (NameAndValue x : arrayB) map.put(x.getName(), x); for (int i = 0; i < arrayA.size(); i++) arrayB.set(i, map.get(arrayA.get(i).getName())); … Read more
[ad_1] No, there is no approach to do this, you need the internet permission as this allows android to use internet protocols (like TCP, Transmission Control Protocol which is one of the core protocols and is needed to send POST data -via a HTTP request-) So without the INTERNET permission there can be no data … Read more
[ad_1] With ggplot, it is essential to have a single data frame with everything in it (at least for a single plotting layer, e.g., all the bars in a plot). You create a data frame of the column sums, and then try to use external vectors for the id and the grouping, which makes things … Read more
[ad_1] If you make each state have unique color, you can check the pixel color on the clicked point: public boolean onTouch (View v, MotionEvent ev) { final int action = ev.getAction(); final int evX = (int) ev.getX(); final int evY = (int) ev.getY(); switch (action) { case MotionEvent.ACTION_DOWN : break; case MotionEvent.ACTION_UP : ImageView … Read more
[ad_1] SELECT t1.ID ,t1.NAME ,t1.Grade ,t1.Marks FROM t1 INNER JOIN ( SELECT Grade ,max(Marks) AS highest_marks FROM t1 GROUP BY Grade ) AS TEMP ON t1.Marks = TEMP.highest_marks AND t1.Grade = TEMP.Grade 1 [ad_2] solved SQL Server group by clause and display all columns [closed]
[ad_1] I don’t really see the problem. In addition to creating a new certificate, you actually have to use it when you sign. If you use the old one it doesn’t matter. And it isn’t the keystore (a keystore can contain multiple certificates) that is the problem. you have to make sure you use the … Read more
[ad_1] Use style for inline css <%= link_to ‘Explore’, explore_path, style: “color: red;” %> or use class <%= link_to ‘Explore’, explore_path, class: “link-color” %> and in stylesheet .link-color{ color: “red”; } 2 [ad_2] solved How to change the color of link button in .erb template
[ad_1] Switch is a reserved word in Java. Used for the switch … case construct. You have named your method switch, which is not allowed. The first group of errors you are getting are because when you use j = switch(j), it sees the word switch as the start of a switch construct and then … Read more
[ad_1] Your code works fine for me using your (slightly edited) sample data: data = [{‘id’: 1, ‘name’: ‘test’}, {‘id’: 2, ‘name’: ‘test’}, {‘id’: 3, ‘name’: ‘test’}] val = [x[‘id’] for x in data if x[‘name’] == ‘test’][0] >>> print(val) 1 However, if there is no dictionary containing a name that matches the target string: … Read more
[ad_1] CONCLUSION – 07-25-2021 After looking at this problem in more detail, I believe that it is NOT technically possible to use Python Requests to scrape the website and table in your question. Which means that your question cannot be solved in the manner that you would prefer. Why? The website employs anti-scraping mechanisms. The … Read more
[ad_1] If you are Sorting columns A to H you could use the below Columns(“A:H”).Select ActiveWorkbook.Worksheets(“Sheet1”).Sort.SortFields.Clear ActiveWorkbook.Worksheets(“Sheet1”).Sort.SortFields.Add Key:=Range(“B:B”), _ SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal ActiveWorkbook.Worksheets(“Sheet1”).Sort.SortFields.Add Key:=Range(“H:H”), _ SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal With ActiveWorkbook.Worksheets(“Sheet1”).Sort .SetRange Range(“A:H”) .Header = xlYes .MatchCase = False .Orientation = xlTopToBottom .SortMethod = xlPinYin .Apply End With All you needed to do was record the … Read more
[ad_1] The C Programming Language (second edition): Exercise 1-15 (Celsius to Fahrenheit conversion) – What is wrong with my solution? [duplicate] [ad_2] solved The C Programming Language (second edition): Exercise 1-15 (Celsius to Fahrenheit conversion) – What is wrong with my solution? [duplicate]
[ad_1] Your comparison code is fine. The problem is that you’re not calling the function correctly. You need to call the member function through an object. Otherwise, how will it know that it should be comparing with pepper? if (pepper.sameAge(salty)) { // do something } This is basic to all object-oriented programming — methods are … Read more