Kirat[ad_1] Add text to a list and print it. Here I am adding the text to res list and printing it. res = [] for item in data: text = item.get_text().strip().replace(‘ ‘, ”) res.append(text) # printing the res list print(res) 2 [ad_2] solved How can I divide the values one by one in python? [closed]
[ad_1] If you check the Resources tab of that fiddle, it actually says it includes jQuery: Mind that $ isn’t standard JavaScript, but a jQuery function/API to start with. 4 [ad_2] solved In jsfiddle, it works in pure javascript, But – when I include this in my code, it doesn’t work without jquery included [closed]
[ad_1] Add this into your CSS: @media(max-width: 360px) { .email-message br { display: none; } } use some ID or class to encapsulate it’s effect inside the elements you specifically need, otherwise it will get rid of all br tags in mobile. If this is what you want, simply do: @media(max-width: 360px) { br { … Read more
[ad_1] I run the following code and expect to get all the words from the link below in a list without repeating any word. How determine if a word is unique? [ad_2] solved I run the following code and expect to get all the words from the link below in a list without repeating any … Read more
[ad_1] i hope now you will able to understand the concept of Logical AND (&&) :- Condition 1 Condition2 Output true true true true false false false true false false false false one the TRUE + TRUE Output will be TRUE otherwise output will be FALSE. [ad_2] solved Result from printing statement and if statement … Read more
[ad_1] First, pass Address class as parameter. void setAddress(Address s) Since Address in a static nested class, but you have declared Address as String in your Problem3_1 class file. So you will need to concat the values manually like void setAddress(Address s) { //address = s; address = s.number + ” , ” + s.street; … Read more
[ad_1] Simply count the number of attempts and exit the loop once it reaches the threshold. Like that: int attemptsNum = 0; final int maxAttempts = 3; do { System.out.print(“Guess a number between 1 and 10: “); user = input.nextInt(); if (user > comp) System.out.println(“My number is less than ” + user + “.”); else … Read more
[ad_1] If you’re looking to create a 2D array you should take a look at this Stack Overflow post here. It has a nice image to explain how 2D memory is laid out and how to properly create the array. Remember, when you create dynamic memory using new you need to delete the memory manually … Read more
[ad_1] Assuming your split criteria is by fixed number of characters (e.g. 5 here), you can use: df[‘dfnewcolumn1’] = df[‘dfcolumn’].str[:5] df[‘dfnewcolumn2’] = df[‘dfcolumn’].str[5:] Result: dfcolumn dfnewcolumn1 dfnewcolumn2 0 PUEF2CarmenXFc034DpEd PUEF2 CarmenXFc034DpEd 1 PUEF2BalulanFc034CamH PUEF2 BalulanFc034CamH 2 CARF1BalulanFc013Baca CARF1 BalulanFc013Baca If your split criteria is by the first digit in the string, you can use: df[[‘dfnewcolumn1’, … Read more
[ad_1] You should create an empty list and keep appending the dates: import datetime def date_range(): result = [] current = datetime.date(2021, 3, 1) end = datetime.date(2021, 3, 31) delta = datetime.timedelta(days=1) while current <= end: result.append(current) current += delta return result print(date_range()) Of course, you can pass start and end as parameters, which makes … Read more
[ad_1] The error got resolved by @Someprogrammerdude comment about a is_same_v helper variable template defined here. My final code is #ifdef My_OLD_TOOL_CHAIN template< class T, class U > inline constexpr bool is_same_v = std::is_same<T, U>::value; template<class T, class O = T> using IteratorOnly = std::enable_if_t< !is_same_v<typename std::iterator_traits<T>::value_type, void>, O >; #else // My_OLD_TOOL_CHAIN template<class T, … Read more
[ad_1] There are several ways to do this. But since the size of the array is always 6×7, you can actually create a kind of template array as an array literal, which starts with 0. Then the rest is a piece of cake: just add the argument to all the values: function snakeArray(start) { return … Read more
[ad_1] I just did it for the date. You can copy the implementation made in C# in dart. DateTime.DateToTicks(…) void main() { final dateTime = DateTime.now(); print(DateTimeUtils.dateToTicks( dateTime.year, dateTime.month, dateTime.day, )); } class DateTimeUtils { static const int TicksPerMillisecond = 10000; static const int TicksPerSecond = TicksPerMillisecond * 1000; static const int TicksPerMinute = TicksPerSecond … Read more
[ad_1] $(document) does not guarantee the fact that it is loaded. to do this, you’ll need to either: Bind to DOM the old-school way Wrap a closure Make sure the script is loaded after jQuery (i.e. its script tag is after) [ad_2] solved Missing step in jQuery and getting “ReferenceError: $ is not defined”
[ad_1] Adding an example code (the thing you’d already tried) is not only polite on StackOverflow, but also helps answering question about your problem – it’s easier to help with an example. But, I’ll give it a try now: const people = [‘Mary’, ‘Paul’, ‘John’, ‘Lisa’, ‘Mary’, ‘Mary’, ‘Paul’, ‘Lisa’]; // counting the names & … Read more