[Solved] Php – echo line 6 from Text file
[ad_1] echo implode(‘<br />’, array_slice(file(‘file/datum2.html’), 0, 6)); OR echo implode(‘\n’, array_slice(file(‘file/datum2.html’), 0, 6)); 7 [ad_2] solved Php – echo line 6 from Text file
[ad_1] echo implode(‘<br />’, array_slice(file(‘file/datum2.html’), 0, 6)); OR echo implode(‘\n’, array_slice(file(‘file/datum2.html’), 0, 6)); 7 [ad_2] solved Php – echo line 6 from Text file
[ad_1] When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed] [ad_2] solved When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed]
[ad_1] Try this layout. <RelativeLayout xmlns:android=”http://schemas.android.com/apk/res/android” xmlns:app=”http://schemas.android.com/apk/res-auto” android:layout_width=”fill_parent” android:layout_height=”fill_parent”> <ImageView android:id=”@+id/imageView” android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:layout_alignParentEnd=”true” android:layout_alignParentStart=”true” android:layout_alignParentTop=”true” android:src=”https://stackoverflow.com/questions/38821397/@mipmap/ic_launcher” /> <LinearLayout android:layout_width=”match_parent” android:layout_height=”wrap_content” android:layout_centerHorizontal=”true” android:orientation=”horizontal” android:layout_above=”@+id/imageView2″ android:layout_below=”@+id/imageView”></LinearLayout> <ImageView android:id=”@+id/imageView2″ android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:src=”https://stackoverflow.com/questions/38821397/@mipmap/ic_launcher” android:layout_alignParentEnd=”true” android:layout_alignParentStart=”true” android:layout_alignParentBottom=”true” /> </RelativeLayout> [ad_2] solved android ImageView allways top and bottom [closed]
[ad_1] A bit untidy, but does the job: d <- data.frame(a=a[-(1:2)], diff=diff(a, 2)) d$br <- 0 for (i in 1:nrow(d)) { if (i==1 & d$diff[1]==2) { d$br[1] <- 1 } else if (i==2 & d$diff[2]==2 & d$br[1]!=1) { d$br[2] <- 1 } if (d$diff[i]==2 & !any(sum(d$br[c(i-1, i-2)])>0)) d$br[i] <- 1 } t(sapply(d$a[d$br==1], function(x) (x-2):x)) # … Read more
[ad_1] The command strcat(a[0],”\0″); is working on strings which are already terminated by \0. Otherwise it doesn’t know where to append the second string. In your case a[0] is not terminated, so the function will induce undefined behavior. You can do the following instead: a[0][n] = ‘\0’; (the same is for the rest of a … Read more
[ad_1] Thanks @Peter urlLogin := “http://kasant.gvc.oao.rzd:8888/kasant/login?” formData := url.Values{ “dor_user”: {“51”}, “login”: {“nvivc”}, “pass”: {“51256”}, } cookieJar, _ := cookiejar.New(nil) client := &http.Client{ Jar: cookieJar, } respp, _ := client.Post(urlLogin, “application/x-www-form-urlencoded”, bytes.NewBufferString(formData.Encode())) defer respp.Body.Close() [ad_2] solved I can not send a post request with Golang?
[ad_1] Map<String, List<String>> newMap = new HashMap<>(); for (Map.Entry<String, String> entry : masterList.entrySet()) { List<String> values = new LinkedList<>(); if (entry.getKey().startsWith(“tag_”)) { String[] words = entry.getValue().split(“,\\s*”); Collections.addAll(values, words); } else { values.add(entry.getValue()); } newMap.put(entry.getKey(), values); } One should not change the type of the map, so need to create a new map. [ad_2] solved How … Read more
[ad_1] I need to replace : with “:” form the string “AAAA:123346hadhdhajkkd890” result like “AAAA”:”123346hadhdhajkkd890″ using Replace functionality in C# [ad_2] solved I need to replace : with “:” form the string “AAAA:123346hadhdhajkkd890” result like “AAAA”:”123346hadhdhajkkd890″ using Replace functionality in C#
[ad_1] I recommend https://bookdown.org/ndphillips/YaRrr/ as a good introduction to R that includes a big section on data visualisation. [ad_2] solved Need Pictorial representation for the below question, (eg: histogram,swarmplot,etc)
[ad_1] If you have just two arrays, you could use the object spread operator to do something like the following: function combine(arr1, arr2) { return arr1.map((obj, idx) => ({ …obj, …arr2[idx] })); } var arr1 = [ { name: “abc” }, { name: “xyz” } ]; var arr2 = [ { age: 18 }, { … Read more
[ad_1] So basically instead of adding the values on the return just [(x, y) for x in [2,3,4] for y in [2,4,5] if x+y==7] I expect this will give you the desired output you asked for. [ad_2] solved How to get tuple of numbers that fulfill a condition? [closed]
[ad_1] Try this javascript: var ua = navigator.userAgent.toLowerCase(); var isAndroid = ua.indexOf(“android”) > -1; //&& ua.indexOf(“mobile”); if(isAndroid) { // Do something! } [ad_2] solved When someone opens my website made in wordpress on a mobile device, to offer an Android app
[ad_1] Use this class for your purpose with files ! Hope it will help you ! public class MyJSON { static String fileName = “myBlog.json”; public static void saveData(Context context, String mJsonResponse) { try { FileWriter file = new FileWriter(context.getFilesDir().getPath() + “https://stackoverflow.com/” + fileName); file.write(mJsonResponse); file.flush(); file.close(); } catch (IOException e) { Log.e(“TAG”, “Error in … Read more
[ad_1] Lodash allow you to do that pretty easily: var sortedDept = _.groupBy(arr, function(ite){return ite.deptName}); Now you can access by sortedDept.Marketing –> give you an array with only marketing related object. And just display those values. 2 [ad_2] solved JavaScript object array Group By and Get values
[ad_1] After eliminating useless code, renaming variables and formatting it: private static void Sort(int[] array) { for (int j = 1; j < array.length; j++) { int value = array[j]; int index = j-1; while ( (index >= 0) && (array[index] < value) ) { array[index + 1] = array[index]; index–; } array[index + 1] … Read more