[Solved] How is transforming this iterator block a functional change?

[ad_1] The two are not equivalent. The semantics of how execution is deferred between the two Bar methods is different. Foo.Bar will evaluate Sequence into an IEnumerable value when you call Bar. Foo2.Bar2 will evaluate Sequence into the value in that variable when you enumerate the sequence returned by Bar2. We can write a simple … Read more

[Solved] Dynamic FieldName for GridViewDataTextColumn ()

[ad_1] No, in general. The GridViewDataTextColumn is a hierarchycal (non Data-Bound) element and it is not contained into a Data-Bound container. According to the exception’s message, I believe this is a common situation for such an ASP.NET controls: DataBinding expressions are only supported on objects that have a DataBinding event. I believe it is possible … Read more

[Solved] EKCalendar on my ipad application

[ad_1] Finally I found a solution for this. ….>In appdelegate (void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification { UIApplicationState state = [application applicationState]; if (state == UIApplicationStateActive) { UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@”Reminder” message:notification.alertBody delegate:self cancelButtonTitle:@”OK” otherButtonTitles:nil]; [alert show]; } // Request to reload table view data [[NSNotificationCenter defaultCenter] postNotificationName:@”Notification” object:self]; } ….>create reminder-SecondClass(Save Action) UILocalNotification* localNotification … Read more

[Solved] Passing String from one class to another

[ad_1] There are two ways: create an instance of your printer class and evoke the method on the printer object: public class MyPrinter { public void printString( String string ) { System.out.println( string ); } } in your main: MyPrinter myPrinter = new MyPrinter(); myPrinter.printString( input ); or 2. you create a static method in … Read more

[Solved] Alert view with JSON data [closed]

[ad_1] Don’t use NSDictionary in swift. Use [String:Any]. Get all values of the dictionary and join the array of strings. And join the error with a new line as a separator. let jsonObj:[String: Any] = [“error”: [ “email”: [“The email has already been taken.”], “phone”: [“The phone has already been taken.”]] ] if let errorMsgs … Read more

[Solved] How to disable all the above checkbox options If someone click on None of the above checkbox? [closed]

[ad_1] Please use this code I hope it’s helpful for you. Thanks <input type=”checkbox” name=”check” value=”father” class=”group1″>Father <input type=”checkbox” name=”check” value=”mother” class=”group1″>mother <input type=”checkbox” name=”check” value=”son & doughter” class=”group1″>son & doughter <input type=”checkbox” name=”check” value=”none” id=”none” class=”group1″>none $(function(){ $(“#none”).on(“click”,function(){ if (this.checked) { $(“input.group1”).attr(“disabled”, true); }else{ $(“input.group1”).attr(“disabled”, false); } }); }); [ad_2] solved How to disable … Read more

[Solved] An unhandled exception occurred while processing the request in cosmos db and asp.net core

[ad_1] The stack trace points to a NotFound in OperationType Read, ResourceType Collection. This means that the Uri that you are passing, is not pointing to a collection that exists in that account. You are creating the Uri using: UriFactory.CreateDocumentCollectionUri(_azureCosmosDbOptions.Value.DatabaseId, “catlogdb”) Check the value of _azureCosmosDbOptions.Value.DatabaseId and verify it is valid and it’s the one … Read more

[Solved] Can not implicitly convert type IEnumerable

[ad_1] Error is due to the return type of your method. Change it to return IEnumerable<SourceModel> as you are getting IEnumerable<SourceModel> from database public static IEnumerable<SourceModel> GetRecord(string ID) { var recs = Source.GetRecords(ID); return recs; // no error now as you are returning list } [ad_2] solved Can not implicitly convert type IEnumerable

[Solved] How to compare this two hashes in ruby [closed]

[ad_1] 1. Symbolize keys These hashes are not equal because the keys are not equal. If you want to compare the values, no matter whether the keys are strings or symbols you can just transform the keys using to_sym. (Note that this will not transform nested keys). first_hash.transform_keys(&:to_sym) == second_hash.transform_keys(&:to_sym) 2. Compare as JSON (NOT … Read more