Kirat[ad_1] If you have all names in file (e.g. names.txt): Baynes, Aron Bazemore, Kent Beal, Bradley Beasley, Malik Beasley, Michael Belinelli, Marco Bell, Jordan Bembry, DeAndre’ You can: Read line split line (using separator) display in reverse way import java.io.BufferedReader; import java.io.FileReader; public class Main { public static void main(String[] args) { // File name … Read more
[ad_1] If you want to use recursive method why use loop in it…? I have write simple method which returns the reverse string using recursion. public string ReverseString(string s) { if (s == null || s.Length <= 1) // if length is less or equal 1 then also returns return s; return ReverseString(s.Substring(1)) + s[0]; … Read more
[ad_1] str = “IV_04.03.2019-10-56-45_example_c584536f-ab26-40ce-b5b6-386f755ba747_1.csv” s1= str.split(“_”)[2] s2= str.split(“_”)[3] print (s1) print (s2) output: example c584536f-ab26-40ce-b5b6-386f755ba747 3 [ad_2] solved How to get string between two underscores? [closed]
[ad_1] Try this: List<String> actual = new ArrayList<>(); List<String> required = new ArrayList<>(); List<String> common = new ArrayList<>(actual); common.retainAll(required); System.out.println(” 100.0 * common / actual = ” + (actual.size() == 0 ? 0 : 100.0 * common.size() / actual.size())); System.out.println(” 100.0 * common / required = ” + (required.size() == 0 ? 0 : 100.0 … Read more
[ad_1] Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] – heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, … Read more
[ad_1] for(int a=0;a<200;a++){ for(int g=0;g<200;g++){ char str[10]; snprintf(str, 10, “%d,%d”, a,g); key = [NSString stringWithCString:str encoding:NSASCIIStringEncoding]; } } Runs 4 times as fast on my old ipod touch 2g Time old: 4.303022833333 Time new: 1.117406833333 3 [ad_2] solved Is there a way to speed up this Objective-C string assignment?
[ad_1] 1> Why can’t i remove from tkinter import* from the last_function file.. cause anyway it’s got that on the top of the file that’s calling it right.Why do i get an error saying IntVar() not defined The Python “import” follows the same scoping rules as the rest of the Python language. By “import” at … Read more
[ad_1] The expression ++i || ++j && ++k will group like so due to precedence: ++i || (++j && ++k) One of the few rules C has about evaluation order of expressions is that the left-hand side of the || and the `&& operators must execute before the right-hand side (for short circuiting). This is … Read more
[ad_1] Java doesn’t support operator overloading, instead you need to add an add function: public class Money { private BigDecimal amount; private Currency currency; public Money add(Money m) { Money res = new Money(); if (!currency.equals(m.currency)) { throw new UnsupportedOperationException(); } res.currency = currency; res.amount = m.amount.add(amount); return res; } } Money result = one.add(two); … Read more
[ad_1] Accordingly your issue the regular expression is quite simple. /\.(jpe?g|png|gif|bmp)$/i Do you really sure that nothing else will be used? For example, JPEG format allows both .jpg and .jpeg extensions. That’s why I put e? pattern in the regular expression. Example of validation could be as follows: var filename = “/site/images/test.png”; if ( /\.(jpe?g|png|gif|bmp)$/i.test(filename) … Read more
[ad_1] Algorithm input = [2,5,1,4,7,3,1,2,3] output = [[]] for idx,val in enumerate(input): if idx > 0 and input[idx-1] > input[idx]: output.append([val]) else: output[-1].append(val) print output Output is [[2, 5], [1, 4, 7], [3], [1, 2, 3]] Explanation of the algorithm in words: Create an output list with an empty sublist. Enumerate over the input list. … Read more
[ad_1] Time complexity of program is usually calculated based on the number of inputs. For the programs like one u have given, the complexity is always constant so the time complexity is O(1). Read a bit about the complexity of algorithms then u will get a clear picture. I would suggest an algorithm book by … Read more
[ad_1] So if it’s objective c, it’s init and not init() 🙂 just saying… kinda big things… See in java, when you are doing a new MyClass() 2 things happened: the compiler book some space in memory to store your new instance the MyClass constructor is called. now, in objective-C, those 2 thing are separated … Read more
[ad_1] Just create a list and add items to it, List<Integer> checkedList = new ArrayList<Integer>(); for (Product p : boxAdapter.getBox()) { if (p.aBoolean) checkedList.add(p.id); } I would suggest you work on your basics before you start coding, it will help you in such situations. Hope this is the solution you were looking for. 0 [ad_2] … Read more
[ad_1] Try this public void generateQRCode_general(String data, ImageView img)throws WriterException { com.google.zxing.Writer writer = new QRCodeWriter(); String finaldata = Uri.encode(data, characterEncoding); BitMatrix bm = writer.encode(finaldata, BarcodeFormat.QR_CODE,bitmapWidth, bitmapHeight); ImageBitmap = Bitmap.createBitmap(bitmapWidth, bitmapHeight,Config.ARGB_8888); for (int i = 0; i < bitmapWidth; i++) { for (int j = 0; j < bitmapHeight; j++) { ImageBitmap.setPixel(i, j, bm.get(i, j) … Read more