We can see this problem as an instance XOR-SAT problem, though it is more general than the problem posed here, that’s one way to go. Just to gain some intuition I provide a very simple example. Suppose you have systems of three switches and three bulbs like this: S B 1 1, 3 // toggles … Read more
Javascript has a built in atob and btoa function. <script type=”text/javascript”> function doAtob() { var val = document.getElementById(“inputbox”).value; var out = document.getElementById(“outval”); out.appendChild(document.createTextNode(atob(val))); } </script> <input id=”inputbox” type=textbox /> <button onclick=’doAtob()’>Do it!</button> <span id=”outval” /> solved How Do I Execute btoa(string); using HTML and JS
A dictionary maps strings to values. An array maps integers to values. That is about it! So, seriously: in the end, both data structures map a “key set” to values. For dictionaries, the keys can of (almost) arbitrary type, without any constraint on them (besides being “hash able”). Whereas an array maps a consecutive range … Read more
At least part of the problem is that you are not understanding how operators work in C++. for(i=1;i<=n,completed==0;i++){ The expression i<=n,completed==0 has the effect of evaluating i <= n, discarding the result, then evaluating completed == 0, and giving the result of that. So the end condition of the loop is essentially completed == 0. … Read more
Here are the steps to do it: # clone the original repository git clone <url> # Create the second repository on your server # once the repository is created add the second remote git remote add odoo12 <new url> # upload the code to your new repo git push odoo12 –all If you are using … Read more
First of all, this is neither a string nor a list, but a tuple, as indicated by the round brackets. split is a method of the str class, so it can’t be used here. To convert a tuple t into a list, simply do list_1 = list(t) 4 solved How do you explicitly convert a … Read more
textContent replaces all the content in the element. http://jsfiddle.net/2nmL7v5b/6/ You have to something like this var infoDiv = document.createElement(“div”); infoDiv.setAttribute(“class”, “text-block”); var bio = document.createElement(“strong”); bio.textContent = “Bio”; infoDiv.appendChild(bio); var spanElem = document.createElement(“div”); spanElem.textContent = “Full”; infoDiv.appendChild(spanElem) document.getElementsByTagName(“body”)[0].appendChild(infoDiv) <body> </body> Or if you don’t want to use span tag you can use innerHTML also like … Read more
Why I am not able to assign string or any other values to the images array?. The Java type system prevents it. An array declared with type Image[] can only hold objects that are Image instances, or instances of a subtype of Image (or null values). The compiler will prevent you from doing that. That … Read more
you might want to solve this like: // main.go import “testapp/app” func main(){ a := app.GetApp() err := a.ConnectDatabase() if err != nil { panic(err.Error()) } a.db. //interesting db code here } // testapp/app.go func (a *App) ConnectDatabase() error{ db, err := sql.Open() if err != nil { return err } a.db = db return … Read more
You have the equal elements in array, when m=8 and l=6=>i=l: in first loop, i=6, condition is i<m, then the execution of next for loop starts and in the second for loop, till j=5<6 condition, there are no equal elements so codes continue with if(i==j){ //i =6, j =6 count++; } in the next execution … Read more
You only need one event listener, and you need to define the a key press state variable (x) outside of the listener function so that it can be referenced by subsequent executions of the listener function. You also need to make sure that you reset the a key press variable after the b key press. … Read more
It really depends on what you wanna be specialized. I strongly recommend “Java”, because it´s a object-oriented language and is used in several different type of hardwares. 1 solved skills required for software development/engineering? [closed]
I could think of following two ways: You will need to use Facebook Graph API to monitor posts by user https://developers.facebook.com/docs/graph-api/reference/v3.0/post. But for that, the user should give permission to your app or the post should be public. Graph API SDK is available for PHP, Javascript, Android, and IOS. Another way I could think is … Read more
Does the String in Map<String, List<A>> related to the output? I assume that you want to get every pair <F, E> from the original map right? So this might help Map<String, List<A>> input; input.values().stream() .flatMap(Collection::stream) .map(a -> a.getListB()) // extract list B from A .flatMap(Collection::stream) // Here you get all B instances .collect( toMap( b … Read more
As per comments I’ve amended the code to copy only the specified range, both Sheets should exist, the code will not create the second Sheet for you: Sub Test() Dim Cell As Range With Sheets(“Sheet1”) ‘Sheet with data to check for value ‘ loop column H untill last cell with value (not entire column) For … Read more