[Solved] Cant find where I did not close my bracket. Uncaught SyntaxError: Unexpected end of input

Took me little long to debug your code but I think I found where the problem is. Actually, the problem isn’t with the code that you have shown us. The problem is somewhere else. You have missed to close two function. Look at the code below: $(document).ready(function () { $(“.newsletter”).colorbox({ iframe: true, width: “500px”, height: … Read more

[Solved] String to String[] [closed]

To convert a string to string[], you can initialize a single-element array: efStudent.sponsor = new string[] { Convert.ToString(student.Sponsor) }; 4 solved String to String[] [closed]

[Solved] Reading and writing a file in byte array in C/C++

Make sure you’re checking the actual size. Windows has different ways of showing it. Compare the “Size” in bytes (e.g.16666) rather than the “size on disk”, which will be rounded up depending on the filesystem. Update Your drop box link has this code like this:- FILE* output = fopen( “test_output.dat”, “wb” ); fwrite( fileBuf, 1, … Read more

[Solved] Convert c++ vector to c-style pointer

Look here vector<vector<double> >a(3,vector<double>(4)); You defined a as a vector having 3 elements of type vector<double>. So a[0] has type vector<double>. vector is a user defined type. It is not a pointer. 2 solved Convert c++ vector to c-style pointer

[Solved] What are the Min and Max variable names length from one million variable names in C++? [closed]

The first character in an identifier must be a-z, A-Z, or underscore, for 53 possibilities. Subsequent characters can be digits 0-9 too, for 63 possibilities. So n characters give 53 * (63**(n-1)) legal identifiers: Length Names 1 53 2 3339 3 210357 // much less than 1000000 4 13252491 // much more than 1000000 Some … Read more

[Solved] How can i create a contingency table in R? [closed]

You should give a reproducible example. Here some data: set.seed(1234) dat <- data.frame(Smoker=sample(c(‘Smoke’,’No_Smoke’),20,rep=TRUE), CANCER=sample(c(‘Cancer’,’NO_Cancer’),20,rep=TRUE)) Then using table you can get your contingency table: table(dat$Smoker,dat$CANCER) Cancer NO_Cancer No_Smoke 7 4 Smoke 5 4 For more information see ?table Description table uses the cross-classifying factors to build a contingency table of the counts at each combination of … Read more

[Solved] Java Chat Client.. using .add methood [closed]

Use ListModel if you want to change the content of a JList dynamically. DefaultListModel listModel = new DefaultListModel(); JList list = new JList(listModel); listModel.addElement(“item”); listModel.addElement(“another item”); 4 solved Java Chat Client.. using .add methood [closed]

[Solved] Show Yes/No messagebox where No is grayed out win32api C++ [closed]

Use SetWindowsHookEx() or SetWinEventHook() with a thread-local hook to capture the MessageBox() dialog’s HWND, then you can use EnableWindow() to disable the button. Here is how to do it using SetWindowsHookEx(): HHOOK hHook = NULL; LRESULT CALLBACK CBTProc(int nCode, WPARAM wParam, LPARAM lParam) { if( nCode == HCBT_ACTIVATE ) { HWND hDlg = (HWND) wParam; … Read more

[Solved] Excel macro to find cells with numbers larger than 20 in a specific column and then divide the matching cells by 1000 [closed]

Let’s say your Kb values start in row 1 of column A, write this formula in column B : =IF(A1>20, A1/1000, A1) Basically, what this does, is tell the computer that if A1 is greater than 20, put A1/1000 in this cell, otherwise put A1. Stretching this formula down the column will give you the … Read more

[Solved] Could someone look at my html5 and css3? [closed]

The problem with the side links in your code is you have <a href=”resume.html#Anchor”> You need to remove resume.html You’re already on that page, you just want the anchor like #Anchor. Same with the “return to top” links. 1 solved Could someone look at my html5 and css3? [closed]

[Solved] Operators I didnot understand [closed]

<< >> These are the shift operators. They shift the left operand by the number of bits given in the right operand. The direction of the shift depends on which of the two operators was used. ^ This is the bitwise exclusive OR operator. The result will have bits set where only one of the … Read more