You can use the following code: def upanddown(n): return range(1, n) + range(n, 0, -1) def triangle(rows): for num in xrange(1, rows + 1): print ‘ ‘.join(map(str, upanddown(num))).center(rows * 4 – 3) rows = input(“Number of rows: “) triangle(rows) Output: Number of rows: 4 1 1 2 1 1 2 3 2 1 1 2 … Read more
Is that you are looking for? <script> $(document).on(“click”, “#quizresultsave”, function(){ $(this).text(“Clicked”); }); $(document).ready(function(){ $(‘#step2continue’).click(function(){ $(“#quizresultsave”).trigger(“click”); }); }); </script> <div id=”step2continue” onclick=””>test tes tes test </div> <div id=”quizresultsave” onclick=”alert(‘tt’)”>testingggggg</div> solved Why trigger function is not working?
If there is a file that you want to open, you can try a file stream. Here is a good look at how to open a file for input and output. Just make sure to check if you can actually open the file before you try to read/write from/to it. You can do it with … Read more
You can get all App info from iTunes store lookup API: http://itunes.apple.com/lookup?bundleId=YOUR_BUNDLE_ID, in this you can get App version on App Store. Make your design screen as you want to show your App users, Then compare your App version on App store & user’s device, if both version not equal then show the update version … Read more
It’s easy: Read you first file line by line (you can use a Scanner for that). For each line, write it to the output file (you can use a PrintWriter for that). Also store the line in a HashSet. Read your second file line by line. For each line, check if the line is in … Read more
Google has a really handy tutorials for this: An overview of Google’s billing setup: https://developer.android.com/google/play/billing/index.html?hl=az Actually implementing it: http://developer.android.com/google/play/billing/billing_integrate.html solved Activity for different paid the application [closed]
Here is a plugin that i used in some project: ScrollMagic With this plugin it’s easy to achieve a similar result like the canvas in your link. 2 solved What type of feature in JS/HTML/CSS is this site using? [closed]
You can simply use two div elements to divide your page to 70% and 30%. I have edited a bit of your CSS and it works: CSS: .sec { width:70%; float:left; background-color: red; margin-bottom: 3em; } .side { width:30%; float:left; background-color:Green; } HTML: <div id=”wrapper”> //your rest of HTML <div class=”sec”> <h1>Last news</h1> <article> <h1>News … Read more
Your header() in code block 2 is calling for plain text. You should set this to a Javascript or HTML type output. Use one of the following header() calls instead. If you have javascript AND html in the output: header(‘Content-Type: text/html’); If your output is javascript ONLY (no html tags): header(‘Content-Type: application/javascript’); 1 solved Javascript … Read more
All browsers that support JavaScript 1.3 which is when the === operator was introduced. (a === true) evaluates to true given that a is true. And because true is exactly the same as true the behaviour is exactly the same. So examples of browsers that don’t support JavaScript are can be seen of this page: … Read more
I am assuming your arr is a POD (plain old data) array. You could make it in C++ a class and overload the operator[] to do runtime index checking. You usually cannot do what you want, and if you could, it would be strongly implementation and operating system dependent. On Linux, access permission to data … Read more
You are asking for 200 tweets and you have only sized your string array to 50, so it blows up on the 51st tweet processed. This code is the problem: var tweets = service.ListTweetsOnHomeTimeline( new ListTweetsOnHomeTimelineOptions { Count = 200 }); string[] twt_id = new string[50]; Either change the number of tweets you are requesting … Read more
You iterate over the list by using for elem in testList, which yields elements of the list and not their indices. >>> b = [1, 3, -4, 5, 5, 3, 2, 1, 4, 8, 9] >>> for i in b: print i, 1 3 -4 5 5 3 2 1 4 8 9 # Whereas … Read more
Add setContentView(R.layout.LAYOUTNAME); in oncreate, before you try to get view by UserProfileFirstName = (EditText) findViewById(R.id.userFirstName); // here LAYOUTNAME is your layout’s name where you define this edittext 1 solved Android EditText setText not working [closed]
What is this concept called in JAVA? This is not a concept , you have named the method same in two un-related classes . If one of the class was sub class of another then depending on the method signature , it would have been overriding or overloading. You would have implemented run time polymorphism … Read more