[ad_1] This is a compact version by using a closure for the sorted character array. var array = [‘car’, ‘incl’, ‘arc’, ‘linc’, ‘rca’, ‘icnl’, ‘meta’, ‘tame’], result = Object.values( array.reduce( (r, s) => (a => ((r[a] = r[a] || []).push(s), r))([…s].sort()), {} ) ); console.log(result); 1 [ad_2] solved Split arrays into multiple arrays based on … Read more
[ad_1] You use JOIN but didn’t use on to connect two table, from your tables you might use actorID columns to be the connected condition. when you use an aggregate function you might use non-aggregate columns in group by SELECT a.lname,a.fname,AVG(c.salary) FROM Actor a JOIN Castings c on a.actorID = c.actorID group by a.lname,a.fname order … Read more
[ad_1] Presumably rhs is empty, and so rhs[0] does not exist. Hence an index out of bounds exception is thrown. Try if(!String.IsNullOrEmpty(rhs) && rhs[0] == ‘+’) … 3 [ad_2] solved Index out of bounds in an if statement [closed]
[ad_1] Add all of your variables to a list and then you can use the max function like so max(lista) num1 = int(input(‘What is the first number?: ‘)) num2 = int(input(‘What is the second number?: ‘)) num3 = int(input(‘What is the third number?: ‘)) lista = [num1, num2, num3] biggest = max(lista) print(f”{biggest} is the … Read more
[ad_1] try this one first away to get data. $check = DB::select(“select * from accounts where username = ?”,[$data[‘username’]]); second away to get data. $check = DB::select(“select * from accounts where username = :userName”,[‘userName’ => $data[‘username’]]); 1 [ad_2] solved Selecting Data from data base SQL
[ad_1] You might want to use use zip functionality to print pairs of values. list1 = [“1”, “2”] list2 = [“3”, “4”] for pair in zip(list1, list2): print i This will print: (‘1’, ‘3’) (‘2’, ‘4’) Please notice that the lists should be at the same size. 2 [ad_2] solved Print a single string from … Read more
[ad_1] Instead of + it should be ~. With ~ the elements don’t need to be directly behind the input. $(document).ready(function() { $(‘.input’).append(‘<div class=”expander”></div>’); }); .input { position: relative; height: 5.85714rem } .input input { outline: 0; width: 100%; border: none; background: 0 0; border-bottom: .07143rem solid rgba(0, 0, 0, .42); font-size: 1.14286rem; padding-bottom: .57143rem; … Read more
[ad_1] “Better” is arguable, but you could use the built-in method UnionWith and some LINQ for a nice one liner to replace your foreach. Think of it as the closest equivalent to an AddRange, except with the restrictions of a set of course. values.Clear(); values.UnionWith(_values.Select(x => x.Trim())); 2 [ad_2] solved Trim HashSet
[ad_1] Check your formdata, this is not a solution but will help you debug your own code. <script type=”text/javascript”> $(document).ready(function(e){ $(‘#upload’).click(function(e){ var formData = new FormData($(‘form’)[0]); var page = $(“#machine option:selected”).val(); //check the output here e.preventDefault(); console.log(“formData”,formData) $.ajax({ url: page, type: ‘POST’, data: formData, cache: false, contenType: false, processData: false, success: function(data){ $(“#information”).empty(); $(“#information”).append(data); } … Read more
[ad_1] Answer 1.Declared a array list. List<String> productPrice = new ArrayList<String>(); 2.Stored a string object in that array list fname = obj1.getPrice(); productPrice.add(fname); 3.And in last used text utils for joining that array list items via comma. android.text.TextUtils.join(“,”, productPrice); [ad_2] solved seprate object data via coma for every item but not last
[ad_1] Thanks to @blackapps for the suggestion. I found out that the answer of my silly question is quite simple. I insist in using URLUtil.guessFileName(url,contentDisposition,mimeType)) because when I download the pdf file, the downloaded filename will be the same with the uploaded filename in my client’s website. So what I just did is adding this … Read more
[ad_1] http://maven.apache.org/ref/3.5.0/maven-core/lifecycles.html lists 3 lifecycles: default (briefly, this is compile -> test -> package (jar/war/ear/…) -> install -> verify -> deploy) clean (just clean) site (generates project documentation and reports) [ad_2] solved Difference between all java life cycles
[ad_1] Assuming the “df” dataframe has the relevant variables under the names “channel” and “email”, then: To get the number of unique channel-email pairs: dim(unique(df[c(“channel”, “email”)]))[1] To get the sum of all channel-email observations: sum(table(df$channel, df$email)) To get the number of duplicates, simply subtract the former from the later: sum(table(df$channel, df$email)) – dim(unique(df[c(“channel”, “email”)]))[1] 0 … Read more
[ad_1] Your password is not correct, try connect with: mysql -u root -p<YOUR_PASSWORD_HERE> Or, use mysqlsafe and change your root password. 1 [ad_2] solved mysql_exceptions.OperationalError | _mysql_exceptions.OperationalError: (1045, “Access denied for user ‘root’@’localhost’ (using password: YES)”) [closed]
[ad_1] You can use forEach to get all elements that fit the condition: const arr = [12,59,42,53,6]; const x = 24; const y = 4; arr.forEach(function(item, index){ if(item * y === x) { console.log(item, index); } }); [ad_2] solved Determine which element of an array will make IF statement return true Javascript [closed]