[Solved] My website doesn’t load jQuery [closed]

[ad_1] You made two mistakes: You put the link to the jQuery library inside the type attribute, instead of the src You are trying to load the scripts that make use of jQuery before jQuery itself Try this <script type=”text/javascript” src=”https://stackoverflow.com/questions/33256891/js/app/jQuery.min.js”></script> <script type=”text/javascript” src=”js/script.js”></script> 1 [ad_2] solved My website doesn’t load jQuery [closed]

[Solved] Expected type after as

[ad_1] as? is use to cast one type to another, you are asking Xcode to cast response to another type, but haven’t told it what to cast it to. As the error says, its expecting to see a type after the keyword as 2 [ad_2] solved Expected type after as

[Solved] Change the type between str and the name of list

[ad_1] I’m considering you have a string answer stored in the variable c and you want to access a list with the respective name. With this objective, you can use the python function eval(). From the python docs (here) you have that: eval(expression[, globals[, locals]]) The expression argument is parsed and evaluated as a Python … Read more

[Solved] Can we lock a phone with iOS programatically?

[ad_1] Short answer: You can’t. Long Answer: For the security of iOS users, Apple does not allow any application to work with important hardware matters, such as locking the iPhone or controlling the usage of other apps. If your app even attempts to do such a thing (using any method, like external APIs), your app … Read more

[Solved] Why do keys() and items() methods return different Boolean values for same key? (Python 3.6) [closed]

[ad_1] items() contains tuples, key-value pairs: >>> spam.items() dict_items([(‘name’, ‘Zophie’), (‘age’, 7)]) Your key is not such a tuple. It may be contained in one of the tuples, but in does not test for containment recursively. Either test for the correct key-value tuple: >>> (‘name’, ‘Zophie’) in spam.items() True or if you can’t get access … Read more

[Solved] Python .join() format error

[ad_1] It was already said that the delimiter is inserted between each element not added to each element. However you can easily create a new list with the correctly added bear, for example: >>> lst = [‘brown’, ‘polar’, ‘grizzly’, ‘sun’, ‘kodiak’] >>> newlst = [item + ‘ bear’ for item in lst] >>> print(‘\n’.join(newlst)) brown … Read more